# Calculo de perdidas en tuberias

Páginas: 4 (767 palabras) Publicado: 22 de septiembre de 2010
½ in
Re=vDρμ=2.55 ms0.0158 m(1000 kgm3)0.001 pa=4.029X104
ϵD=0.05mm15.8 mm=0.003 F=0.029
HL=FLv22gD=0.0292m(2.55 ms)219.62 ms2(0.0158m)=1.21 mca
HL=0.0291.4m( 2.55ms)219.62ms2(0.0158m)=0.85 mca
HL=0.0291m( 2.55ms)219.62 ms2(0.0158m)= 0.60mca
HL=0.0293m( 2.55ms)219.62 ms2(0.0158m)=1.82 mca
HL=0.0290.4m( 2.55ms)219.62 ms2(0.0158m)= 0.24mca
¾ in
Re=vDρμ=2.88ms0.021 m(1000 kgm3)0.001 pa=6.0X104mca
ϵD=0.05mm21 mm=0.02 F=0.026
HL=FLv22gD=0.0261m(2.88 ms)219.62 ms2(0.021m)=0.52 mca
HL=0.0262m(2.88 ms)219.62 ms2(0.021m)=1.04 mca
1 inRe=vDρμ=2.69 ms0.0266 m(1000 kgm3)0.001 pa=7.1X104mca
ϵD=0.05mm26.6 mm=0.0018 F=0.0245
HL=FLv22gD=0.02456m(2.69 ms)219.62 ms2(0.0266m)=2.03 mca

1 ¼ in (Tramo A-B)
Re=vDρμ=2.58ms0.0351m(1000kgm3)0.001 pa=9.0X104mca
ϵD=0.05mm35.1mm=0.0014 F=0.0228
HL=FLv22gD=0.02283m(2.58 ms)219.62 ms2(0.0351m)=0.66 mca
1 ½ in (Tramo B-C)
Re=vDρμ=3.04ms0.0409m(1000 kgm3)0.001 pa=1.2X105mcaϵD=0.05mm40.9mm=0.0012 F=0.0218
HL=FLv22gD=0.02183m(3.04 ms)219.62 ms2(0.0409m)=0.75 mca
1 ½ in (Tramo C-D)
Re=vDρμ=3.80ms0.0409m(1000 kgm3)0.001 pa=1.55X105mcaϵD=0.05mm40.9mm=0.0012 F=0.0218
HL=FLv22gD=0.02184m(3.80 ms)219.62 ms2(0.0409m)=1.5 mca
2in (Tramo D-E)
Re=vDρμ=3.0ms0.0525m(1000 kgm3)0.001 pa=1.5X105mca
ϵD=0.05mm52.5mm=0.00095 F=0.02HL=FLv22gD=0.023m(3.0 ms)219.62 ms2(0.0525m)=0.52 mca
2in (Tramo E-F)
Re=vDρμ=3.4ms0.0525m(1000 kgm3)0.001 pa=1.7X105mca
ϵD=0.05mm52.5mm=0.00095 F=0.025
HL=FLv22gD=0.0254m(3.4 ms)219.62ms2(0.0525m)=1.12 mca

2 ½ in (Tramo F-G)
Re=vDρμ=2.9ms0.0627m(1000 kgm3)0.001 pa=1.8X105mca

ϵD=0.05mm62.7mm=0.00079 F=0.0198
HL=FLv22gD=0.01983m(2.9 ms)219.62 ms2(0.0627m)=0.27 mca
2 ½in (Tramo G-H)
Re=vDρμ=3.23ms0.0627m(1000 kgm3)0.001 pa=2.0X105mca
ϵD=0.05mm62.7mm=0.00079 F=0.0195
HL=FLv22gD=0.01954m(3.23 ms)219.62 ms2(0.0627m)=0.66mca
2 ½ in (Tramo H-I)...

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