# Capacitancias

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• Publicado : 8 de febrero de 2011

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*CALCULOS DE LAS CAPACITANCIAS*
C = qV

Circuito en serie:
C1 = Q1V1 = 9.343 uc4.25 volts = 2.20 uf C3 = Q3V3 = 9.343 uc1.98 volts = 4.72 uf
C2 = Q2V2 = 9.343uc2.83 volts = 3.30 uf C4 = Q4V4 = 9.343 uc0.93 volts = 10.05 uf
VT = V1 + V2 +V3
QT = Q1 = Q2 = Q3
CT = 11C1 + 1 C2 + 1C3
CT =112.2uf + 13.3uf + 14.7uf + 110uf = . 9343 uf
QT = VT (CT) = (10 V) (. 9343 uf ) = 9.343 uc
VT = QTCT = 9.343 uc . 9343 uf = 10 Volts
V1 = Q1C1 = 9.343 uc2.2 uf =4.25 volts V2 = Q2C2 = 9.343 uc3.3 uf = 2.83 volts
V3 = Q3C3 = 9.343 uc4.7 uf = 1.98 volts V4 = Q4C4 = 9.343 uc10 uf = 0.93 volts
UT = QTVT 2 = 9.343 uc(10volts) 2 = 46.715 ujoules
U1 = Q1V1 2 = 9.343 uc(4.25 volts) 2 = 19.854 ujoules
U2 = Q2V2 2 = 9.343 uc(2.83 volts) 2 = 13.220 ujoules
U3 = Q3V3 2 = 9.343 uc(1.98 volts) 2 =9.249 ujoules
U4 = Q4V4 2 = 9.343 uc(0.93 volts) 2 = 4.344 ujoules

C = qV

Circuito en paralelo:
VT = V1 = V2 = V3
C1 = Q1V1 = 22 uc10 volts = 2.2 ufC3 = Q3V3 = 47 uc10 volts = 4.7 uf
C2 = Q2V2 = 33 uc10 volts = 3.3 uf C4 = Q4V4 = 100 uc10 volts = 10 uf
QT = Q1 + Q2 + Q3
CT = C1 + C2 +C3

CT = 2.2 uf + 3.3 uf + 10 uf + 4.7 uf = 20.2 uf
QT = VT (CT) = (10 V) (20.2 uf ) = 202 uc
Q1= V1 (C1) = (10 V) (2.2 uf ) = 22 uc
Q2 = V2 (C2) = (10 V)(3.3 uf ) = 33 uc
Q3 = V3 (C3) = (10 V) (4.7 uf ) = 47 uc
Q4 = V4 (C4) = (10 V) (10 uf ) = 100 uc
UT = QTVT 2 = 202 uc(10 volts) 2 = 2020 ujoules
U1 = Q1V1 2 = 22uc(10 volts) 2 = 220 ujoules
U2 = Q2V2 2 = 33 uc(10 volts) 2 = 330 ujoules
U3 = Q3V3 2 = 47 uc(10 volts) 2 = 470 ujoules
U4 = Q4V4 2 = 100 uc(10 volts) 2 = 1000 ujoules