# Caso b

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• Publicado : 7 de noviembre de 2011

Vista previa del texto
Caso b).- D/I = Cte.
Yns = 0.1654 = 1.2586 Kg
Ynd = 0.8346= 6.3513 Kg
En = 7.61 Kg
Yos = 0.0689 = 1.2408 Kg
Yod = 0.9311= 16.7691 Kg
Do = 18.01 Kg
Yn-1s =?
Yn-1d =? = 16.7691 Kg
En-1 =?

nn-1 etapas

Rn =?
Xns =?
Xnd =? = 10.4178 Kg
Xnin =? = 2.7188 Kg
Fo = 3.63 Kg
Xos = 0.2510 = .9112 Kg
Xod = 0
Xoin = 0.7490 = 2.7188 Kg
R1 = 14.03 Kg
X1s = 0.0636 = .8934 Kg
X1d =0.7425 = 10.4178 Kg
X1in = 0.19378 = 2.7188 Kg

Do y En-1
Yod = Yn-1d
16.7691 Kg = Yn-1d

R1 y Rn
X1d = Xnd
10.4178 Kg = Xnd

Kg de soluto En = Kg de soluto Rn
Kg disolvente EnKg disolvente Rn

1.2586 = Kg soluto Rn
6.3513 10.4178

Kg de soluto Rn = (1.2586/6.3513) * 10.4178 = 2.0644 Kg
Soluto en Rn = 2.0644 Kg

Rn = 10.4178 + 2.7188 + 2.0644 Kg
Rn =15.201 Kg

2.0644 / 15.201=0 .1358 Fracción de solutos en Rn
10.4178 / 15.201 = 0.6853 Fracción de disolvente en Rn
2.7188 / 15.201 = 0.1788 Fracción de inertes en Rn

Balance en la etapa n.Fo + En-1 = En + Rn
En-1 = 7.61+ 15.201 – 3.63 Kg
En-1 = 19.181 Kg

Kg de soluto en En-1 = 19.181 – 16.7691 = 1.6717 Kg
Soluto en En-1 = 2.4119 Kg

2.4119 / 19.181 = 0.1257 Fracción de solutoen En-1
16.7691 / 19.181 = .8742 Fracción de soluto en En-1

Yns = 0.1654 = 1.2586 Kg
Ynd = 0.8346 = 6.3513 Kg
En = 7.61 Kg
Yos = 0.0689 = 1.2408 Kg
Yod = 0.9311 = 16.7691 Kg
Do = 18.01 KgYn-1s = 0.1257 = 2.4119 Kg
Yn-1d = 0.8742 = 16.7691 Kg
En-1 = 19.181 Kg

n

n-1 etapas

Fo = 3.63 Kg
Xos = 0.2510 = .9112 Kg
Xod = 0
Xoin = 0.7490 = 2.7188 Kg
Rn = 15.201 Kg
Xns 0 .1358 =2.0644 Kg
Xnd 0.6853 = 10.4178 Kg
Xnin = 0.1788 = 2.7188 Kg
R1 = 14.03 Kg
X1s = 0.0636 = .8934 Kg
X1d = 0.7425 = 10.4178 Kg
X1in = 0.19378 = 2.7188 Kg

VARIABLE | CORRIENTE | Kg S / Kg D| VALOR |
Xn | Rn | 2.0644 / 10.4178 | 0.19816084 |
Yf | Do | 1.2408 / 16.7691 | 0.07399323 |
Yn-1 | En-1 | 2.4119 / 16.7691 | 0.14383002 |
X1 | R1 | 0.8934 / 10.4178 | 0.08575706 |

n-1 =...