Computacion

Páginas: 8 (1820 palabras) Publicado: 9 de septiembre de 2013
Manual de soluciones
CAPÍTULO III
Ejercicios 3.2
5. 3,500 = C(0.075)(18/12)  C = 31,111.11111 o $31,111.11
6. 7,000 = 65,000(0.0825)(n)  n = 1.305361305 años 470
7. 750 = 17,500(65/360)i  i = 0.237362637 o 23.7362637%
8. 2 = (1 + 0.118 n)  n = 8.47457621 años  8 años, 5 meses, 21 días
9. M = 8,250(1 + 0.175(7/12)) = 9,092.19
10. 9.76/4 = 2.44  es lo mismo
11. M = 14,250(1 +0.073(135/360)) = 14,640.09
12. M = 37,500(1 + 0.15(7/12)) = 40,781.25
13. 8,100 = 7,200(1 + n(0.113))  n = 1.10619469 o 398 días  abril 12
14. 1) M = 15,000(1 + 0.09(3/12)) = $15,337.50
2) C = 1’000,000(1 + 2(4)(0.11))-1 = $531,914.89
3) 25,000 = 23,800(1 + n(0.0012))  n = 42.016 o 42 días
4) 3,200 = 2,000(1 + 32(i))  i = 0.01875 o 0.225 o 22.5% anual
5) 6,000 = 5,200(1 + 0.065n)  n= 2.36686  2.36686 semestres
6) 5’000,000 = C(1 + 0.136(3/12))  C = $4’835,589.94
15. 1) I = 15,337.50 – 15,000 = $337.50
2) I = M – C = $468.09 3) I = $1,200 4) I = $1,200
5) I = $800 6) I = $164,410.06
16. I = 750(0.045) = 33.75  R = I/12 = 2.8125 millones de dólares
17. E = 0.30(25,550) = 7,665 C = 17,885
C1 = x1(1 + 0.158(1/12))-1 = 0.987004441(x1)
C2 = x2(1 +0.158(2/12))-1 = 0.974342319(x2)
 0.987004441(x1) + 0.974342319(x2) = 17,885
x1 = x2 = 17,885/1.961346761 = $9,118.73
 $7,665.00, $9,118.73 y $9,118.73
18. a) M = 15,300(1 + 0.087(3/12)) = 15,632.78
b) 16,700 = 15,300(1 + (0.087/360)n)  n = 378.6342 o 379 días
19. I = 25,000(0.079/12) = 164.58
20. b) C = 4,000(1 + (0.114/12)2)-1 = 3,925.41  Cb = $7,925.41
c) C1 = 2,800(1 + (0.114/12)-1= 2,773.65
C2 = 2,800(1 + (0.114/12)2)-1 = 2,747.79  Cc = C1 + C2 + C3
C3 = 2,800(1 + (0.114/12)3)-1 = 2,722.41  Cc = $8,243.85
 la tercera
21. b) C = 43,000(1 + (0.062/12)3)-1 = 42,343.67  Cb = $77,343.67
c) C1 = 26,000(1 + 0.0051)-1 = 25,866.36
C2 = 26,000(1 + 0.0051(2))-1 = 25,734.08
C3 = 26,000(1 + 0.0051 (3))-1 = 25,603.15  Cc = $77,203.59
Pagarlo de contado
22. C1 = x1(1 + 0.132/12)-1 = 0.989119684(x1)
C2 = x2(1 + (0.132/12)2)-1 = 0.978473581(x2)
C = E + C1 + C2 = 2.967593265(x1) = 350,000  x1 = US $117,940.69
C = E + C1 + C2 =2.967593265(x1) = 350,000  x1 = US $117,940.69
b) I = 3(117,940.69) – 350,000 = US $3,822.07
23. C1 = 12,000(1 + 0.103(2/12))-1 = 11,797.48  E = $8,202.52
24. C1 = 10,300(1 + (0.136/12)3)-1 =9,961.32
C2 = 7,800(1 + (0.136/12)5)-1 = 7,381.70  C = C1 + C2 = $17,343.02
25. M1 = 20,000(1 + 0.198(5/12)) = 21,650.00
M2 = 8,500(1 + 0.198(2/12)) = 8,780.50  M = M2 + M1 = $12,869.50
26. M1 = 23,500(1 + (0.053/360)(100)) = 23,845.97
M2 = 11,922.99(1 + (0.053/360)(118)) = 12,130.12
I = 11,922.99 + 12,130.12 – 23,500 = $553.11
27. 0.30(Precio) = 15,000  Precio = 50,000  C = 35,000C1 = X1(1 + 0.0925/12)-1 = 0.992350631(X1)
C2 = X2(1 + (0.0925/12)2)-1 = 0.984817398(X2)
a) C1 + C2 = 35,000  1.977168029(X1) = 35,000  X1 = X2 = $17,702.09 c/u
b) 0.992350631(X1) + 0.984817398(0.85X1) = 1.8294454(X1) = 35,000
 X1 = 19,131.48  X2 = 16,261.76 $19,131.48, $16,261.76
c) C2 = 0.984817398(15,000) = 14,772.26  C =35,000 – C2 = 20,227.74
 X1 = 20,227.74(1 + 0.0925/12) =20,383.66  $20,383.66, $15,000.00
28. a) M = 40,000(1 + 0.083(6/12)) = $41,660
b) 39,350 = 35,000(1 + i(261/360))  i = 0.17142857 > 0.083
 la segunda, la tasa es mayor
29. 20,312.20 = C(1 + 0.144(230/360))  C = 18,600.92  I = $1,711.28
30. $18,600.92
31. 1.15 C = C(1 + n(0.096))  n = 1.5625 por 360 = 562.5  (a)
32. C = 9,600(1 + 20(0.116/52))-1 = 9,189.9852  (b)
33. M =28,000(1 + 15(0.124/12)) = 32,340  (c)
34. 24,650 = 24.078(1 + (103/360)i)  i = 0.08303  (d)
35. M = C(1 + 3(0.144/12)) = 1.036 C
M = C(1.0028)13 = 1.037 C  (a)
36. C1 = X1(1 + (0.138/12))-1 = 0.988630746(X1)
C2 = X2(1 + 0.0115(3))-1 = 0.966650556(X2)
C3 = X3(1 + 0.0115(5))-1 = 0.945626478(X3)
 2.900907779(X1) = 50,000  X1 = X2 = X3 = 17,235.98 (a)
37. 0.988630746 X1 +...
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