Formulario

Formulario de Cálculo Diferencial e Integral (Página 1 de 2) Rolando ilca P.

2

1 − r
k = n + n
1 − r

x − x

⎜ ⎟ =
x + y
1 2
( )

= ∑ ⎜ ⎟ x y
k

n !n !"n ! 1 2 k

⎜ ⎟
sen cos ⎜ 2 ⎟
⎜ 2 ⎟

a rc co s x

ctgh x =
ln ⎜ ⎟ ,
x > 1
Formulario deCálculo Diferencial e Integral (Página 2 de 2) Jesús Rubí M.

∫
n n−1

− 2 +
1 ⎪⎩ y = f2 t
∫ a2 − u 2
( )
2a a − u

2 2 2

dx 1 − u 2 dx
= ⋅ ln−1 2 2

u u − a

∫a { f ( x ) ± g ( x )} dx = ∫a f ( x ) dx ± ∫a g ( x ) dx
2 u

u ± a du =

u ± a ±

2
ln u + u ± a
2 2
2

a b
a + b

a

x ⇔ f x ≤ g x∀x ∈ a,b 0 0

0 0 : Taylor

x dx
∆x→0 ∆x
∆x→0 ∆x
f x f 0
f ' 0 x
2!

⎩
( ) ⎨ u
-----------------------
| | |( a + b ) ⋅ (a3 − a2 b + ab2 − b3 ) = a4| | ||
|Cálculo Diferencial e Integral VER.4.9 | |− b4 | | | |
| | |( a + b ) ⋅ (a4 − a3b + a2 b2 − ab3 + | || |
| | |b4 ) = a5 + b5 | | | |
| | |a + b ⋅ a5 − a4 b + a3b2 − a2 b3 + | || |
| | |ab4 − b5 = a6 − b6 | | | |
| | |n || | |
| | |( a + b ) ⋅ ⎛ ( −1)k +1 an− k bk| | | |
| | |−1 ⎞ = an + bn ∀ n ∈ `impar | | | |
| | |⎜ ∑ ⎟ | | | |
| ||n | | | |
| | |( a + b ) ⋅ ⎛ ( −1)k +1 an− k bk| | | |
|...