# Informe

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• Publicado : 14 de marzo de 2012

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P2.5: Find the force exerted byQ1(3.0m, 3.0m, 3.0m) = 1.0 C on Q2(6.0m, 9.0m, 3.0m) = 10. nC.

R12 = (6-3)ax + (9-3)ay + (3-3)az = 3 ax + 6 ay m

, so

Fig. P2.5

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Suppose 10.0nC point charges are located on the corners of a square of side 10.0 cm. Locating the square in the x-y plane (at z = 0.00) with one corner at the origin and one corner at P(10.0, 10.0, 0.00) cm,find the total force acting at point P.

We arbitrarily label the charges as shown in Figure P2.6. Then
ROP = 0.1 ax + 0.1 ay

Fig. P2.6
ROP = 0.141 m
aOP = 0.707 ax + 0.707 ay.

and then thetotal (adjusting to 2 significant digits) is:

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1.00 nC point charges are located at (0.00, -2.00, 0.00)m, (0.00, 2.00, 0.00)m, (0.00, 0.00,-2.00)m and (0.00, 0.00, +2.00)m. Find the total force acting on a 1.00 nC charge located at (2.00, 0.00, 0.00)m.

Figure P2.7a shows the situation, but we need only find the x-directed force from oneof the charges on Qt (Figure P2.7b) and multiply this result by 4. Because of the problem’s symmetry, the rest of the components cancel.

so
The force from all charges is then

Fig. P2.7a | Fig.P2.7b |

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P2.8: A 20.0 nCpoint charge exists at P(0.00,0.00,-3.00m). Where must a 10.0 nC charge be located such that the total field is zero at the origin?

For zero field at the origin, we must cancel the +az directed...