# Ing. de materiales

Páginas: 2 (273 palabras) Publicado: 24 de noviembre de 2011
> n1=10;
>> d1=[1 30 1 10 0];
>> FT=tf(n1,d1)

Transfer function:
10
-------------------------
s^4 + 30 s^3 + s^2 + 10 s

>> roots(n1)

ans =

Emptymatrix: 0-by-1

>> roots(d1)

ans =

0
-29.9778
-0.0111 + 0.5775i
-0.0111 - 0.5775i

>> figure(1)-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------
>> rlocus(FT)
>> n2=[20 20];
>> d2=[1 0 1 -2];>> FT=tf(n2,d2)

Transfer function:
20 s + 20
-----------
s^3 + s - 2

>> roots(d2)

ans =

-0.5000 + 1.3229i
-0.5000 - 1.3229i
1.0000

>> figure(2)>> rlocus(FT2)--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

>> n3=20;
>> d3=[1 6 11 6];
>> FT3=tf(n3,d3)

Transfer function:
20
----------------------
s^3 + 6 s^2 + 11 s + 6

>> roots(d3)

ans =-3.0000
-2.0000
-1.0000

>> figure(3)
>> rlocus(FT3)-----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

>> n4=[20 -20];
>> d4=[1 2 4 8];
>> FT4=tf(n4,d4)

Transfer function:
20 s - 20
---------------------
s^3 + 2s^2 + 4 s + 8

>> roots(d4)

ans =

-2.0000
0.0000 + 2.0000i
0.0000 - 2.0000i
>> figure(4)

>> n5=10;
>> d5=[1 14 44 40];
>> FT5=tf(n5,d5)Transfer function:
10
------------------------
s^3 + 14 s^2 + 44 s + 40

>> roots(d5)

ans =

-10.0000
-2.0000
-2.0000

>> figure(5)
>>...

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