Ingenieria Civil
Páginas: 11 (2695 palabras)
Publicado: 15 de mayo de 2012
Mecánica de Suelos (64.08) - Trabajo Práctico Nº1
Parte A - Agregado de Suelos
Ejercicio 1
Wh = Ws = Vtot = γs = a) γh = ?
269,5 220,6 138,9 2,69
g g 3 cm 3 g/cm
γh = (Ws + Ww)/ Vtot = Wh / Vtot γh = 269,5g / 138,9cm b) γd = ? γd = Ws / Vtot γd = 220,6g / 138,9cm c) γsat = ? γsat = (Ws + Vv * γw)/ Vtot Vs = 220,6g / 2,69(g/cm )
3 3 3
=>
γh =
1,94
g/cm
3
=>
γd =1,59
g/cm
3
γs = Ws / Vs ==> Vs = Ws / γs ==>
3
Vs = 56,9
3
82,01 cm
3
cm
3
Vv = Vtot - Vs = (138,9 - 82,01) cm = γsat = (220,6g+ 56,9cm * 1g/cm )/ 138,9cm d) ω= ? ω = Ww / Ws Ww = 269,5g - 220,6g ω = 48,9g / 220,6g Ww = Wh - Ws ==> ==>
3 3
=>
γsat =
2,0
g/cm
3
Ww =
48,9 ω= ω=
g 0,22 22 %
Mecánica de Suelos (64.08) - Trabajo Práctico Nº1e) ω sat = ? ω sat =(Vv * γw) / Ws = (56,9 cm * 1g/cm ) / 220,6g
3 3
ω= ω=
0,26 26 %
f) Sr = ? Sr = Vw / Vv = 48,9 cm / 56,9 cm
3 3
==>
Sr = Sr =
0,86 86 %
g) e= ? e = Vv / Vs = 56,9 cm / 82,01 cm h) n= ? n = Vv / Vtot = 56,9 cm / 138,9 cm Ejercicio 2
3 3 3 3
==>
e=
0,69
==>
n=
0,41
Wh = Vtot = ω= γs = a) e= ?
1425 731 0,151 2,65
g 3 cm g/cm
3emax = emin =
0,72 0,50
e = Vv / Vs
Ww = Ws * ω Ww = Wh - Ws
Ws * ω = Wh - Ws Ws * ( 1 + ω ) = Wh Ws = Vs = Vv = ==> g cm 3 cm
3
Ws = Wh / ( 1 + ω ) = 1425g / ( 1+ 0,151) ==> y Vs = Ws / γs = 1238,05g / 2,65 (g/cm ) Vv = Vtot - Vs = ( 731 - 467,19 ) cm
3 3
1238,05 467,19 263,81
e = Vv / Vs = 263,81 / 467,19 b) Dr = ?
==>
e=
0,56
Dr = (emax - e ) / (emax - emin)==> Dr = Dr = 0,71 71 %
Dr = ( 0,72 - 0,565) / ( 0,72 - 0,50)
Mecánica de Suelos (64.08) - Trabajo Práctico Nº1
Ejercicio 3
Wh = ω= γs = a) γd = ?
345,2 0,235 2,68
g g/cm
3
Probeta D= H= 4,9 10,4 cm cm
γd = Ws / Vtot
Ww = Ws * ω Ww = Wh - Ws
Ws * ω = Wh - Ws Ws * ( 1 + ω ) = Wh ==> Ws = Wh / ( 1 + ω ) = 345,2g / ( 1+ 0,235) Ws = Vtot = π * ( D/2 ) * H = π * ( 4,9 cm/ 2 ) * 10,4 cm = γd = 279,51g / 196,12cm b) e= ? Ws = Vs = Vv = 279,51 104,30 91,82 e = Vv / Vs g cm 3 cm
3 3 2 2
279,51 196,12 1,43
g cm
3
=>
γd =
g/cm3
==> y
Vs = Ws / γs = 279,51g / 2,68 (g/cm ) Vv = Vtot - Vs = ( 196,12 - 104,30 ) cm
3
3
e = Vv / Vs = 91,82 / 104,30 c) Sr = ?
==>
e=
0,88
Ww = Ws * ω = 279,51g * 0,235 = Vw = Ww / γw = 65,69g / 1 g/cm =3
65,69 65,69 0,72 72
g cm
3
Sr = Vw / Vv = 65,69 cm / 91,82 cm
3
3
==>
Sr = Sr =
%
Fórmula alternativa: Sr = (γs*ω) / (γw*e) d) Sr = Vw / Vv = 0,95 Se supone que el Vv no cambia (el agua desplaza al aire)
3 3
Vwfin = Sr * Vv = 0,95 * 91,82 cm ==> Vwagreg = Vwfin - Vwini = (87,23 - 65,69) cm ==>
3
Vwfin =
87,23 Vwagreg =
cm
21,54
cm3
Mecánicade Suelos (64.08) - Trabajo Práctico Nº1
e) ω= ? ω = 87,23 g / 279,51 g ω =Ww / Ws ==> Wwfin= 87,23 ω= ω= Ejercicio 4 g 0,31 31 %
W pic+W w1 = W pic+W w2+Ws= Ws = a) γs = ?
281,6 320,3 62,1
g g g
W pic+W w1 ∆Vw = Vs
W pic+W w2+Ws
(Wpic+W w1)+ Ws - (Wpic+W w2+Ws) = 281,6g + 62,1g - 320,3g = ∆W w ==> ∆Vw = ∆W w / 1 (g/cm ) ∆Vw = Vs = γs = Ws / Vs γs = 62,1g / 23,4cm Ejercicio 5
33
23,4
cm
3
=>
γs =
2,65
g/cm3
Wh = ω= Vtot = γs = a) γd = ?
1790 0,198 945 2,69
g cm 3 g/cm
3
γd = Ws / Vtot
Ww = Ws * ω Ww = Wh - Ws
Ws * ω = Wh - Ws Ws * ( 1 + ω ) = Wh ==> Ws = Wh / ( 1 + ω ) = 1790g / ( 1+ 0,198) Ws = γd = 1494,16g / 945cm
3
1494,16 1,58
g g/cm3
=>
γd =
Mecánica de Suelos (64.08) - Trabajo Práctico Nº1
b) Sr = ? Ws= 1494,16 Sr = Vw / Vv g
3
==>
Vs = Ws / γs = 1494,16g / 2,69 (g/cm ) Vv = Vtot - Vs = ( 945 - 555,45 ) cm 295,84
3 3
3
cm y Vs = 555,45 3 cm Vv = 389,55 Ww = Ws * ω = 1494,16g * 0,198 = Sr = Vw / Vv = 295,84 cm / 389,55 cm
3
g
==> Sr = Sr =
Vw = 0,76 76 %
295,84
cm
3
==>
c) γh = ? Sr = 1
3
γh = Wh / Vtot = γs (1 + ω) / (1 + e) Sr = ω γs / (e γw) ==> e...
Parte A - Agregado de Suelos
Ejercicio 1
Wh = Ws = Vtot = γs = a) γh = ?
269,5 220,6 138,9 2,69
g g 3 cm 3 g/cm
γh = (Ws + Ww)/ Vtot = Wh / Vtot γh = 269,5g / 138,9cm b) γd = ? γd = Ws / Vtot γd = 220,6g / 138,9cm c) γsat = ? γsat = (Ws + Vv * γw)/ Vtot Vs = 220,6g / 2,69(g/cm )
3 3 3
=>
γh =
1,94
g/cm
3
=>
γd =1,59
g/cm
3
γs = Ws / Vs ==> Vs = Ws / γs ==>
3
Vs = 56,9
3
82,01 cm
3
cm
3
Vv = Vtot - Vs = (138,9 - 82,01) cm = γsat = (220,6g+ 56,9cm * 1g/cm )/ 138,9cm d) ω= ? ω = Ww / Ws Ww = 269,5g - 220,6g ω = 48,9g / 220,6g Ww = Wh - Ws ==> ==>
3 3
=>
γsat =
2,0
g/cm
3
Ww =
48,9 ω= ω=
g 0,22 22 %
Mecánica de Suelos (64.08) - Trabajo Práctico Nº1e) ω sat = ? ω sat =(Vv * γw) / Ws = (56,9 cm * 1g/cm ) / 220,6g
3 3
ω= ω=
0,26 26 %
f) Sr = ? Sr = Vw / Vv = 48,9 cm / 56,9 cm
3 3
==>
Sr = Sr =
0,86 86 %
g) e= ? e = Vv / Vs = 56,9 cm / 82,01 cm h) n= ? n = Vv / Vtot = 56,9 cm / 138,9 cm Ejercicio 2
3 3 3 3
==>
e=
0,69
==>
n=
0,41
Wh = Vtot = ω= γs = a) e= ?
1425 731 0,151 2,65
g 3 cm g/cm
3emax = emin =
0,72 0,50
e = Vv / Vs
Ww = Ws * ω Ww = Wh - Ws
Ws * ω = Wh - Ws Ws * ( 1 + ω ) = Wh Ws = Vs = Vv = ==> g cm 3 cm
3
Ws = Wh / ( 1 + ω ) = 1425g / ( 1+ 0,151) ==> y Vs = Ws / γs = 1238,05g / 2,65 (g/cm ) Vv = Vtot - Vs = ( 731 - 467,19 ) cm
3 3
1238,05 467,19 263,81
e = Vv / Vs = 263,81 / 467,19 b) Dr = ?
==>
e=
0,56
Dr = (emax - e ) / (emax - emin)==> Dr = Dr = 0,71 71 %
Dr = ( 0,72 - 0,565) / ( 0,72 - 0,50)
Mecánica de Suelos (64.08) - Trabajo Práctico Nº1
Ejercicio 3
Wh = ω= γs = a) γd = ?
345,2 0,235 2,68
g g/cm
3
Probeta D= H= 4,9 10,4 cm cm
γd = Ws / Vtot
Ww = Ws * ω Ww = Wh - Ws
Ws * ω = Wh - Ws Ws * ( 1 + ω ) = Wh ==> Ws = Wh / ( 1 + ω ) = 345,2g / ( 1+ 0,235) Ws = Vtot = π * ( D/2 ) * H = π * ( 4,9 cm/ 2 ) * 10,4 cm = γd = 279,51g / 196,12cm b) e= ? Ws = Vs = Vv = 279,51 104,30 91,82 e = Vv / Vs g cm 3 cm
3 3 2 2
279,51 196,12 1,43
g cm
3
=>
γd =
g/cm3
==> y
Vs = Ws / γs = 279,51g / 2,68 (g/cm ) Vv = Vtot - Vs = ( 196,12 - 104,30 ) cm
3
3
e = Vv / Vs = 91,82 / 104,30 c) Sr = ?
==>
e=
0,88
Ww = Ws * ω = 279,51g * 0,235 = Vw = Ww / γw = 65,69g / 1 g/cm =3
65,69 65,69 0,72 72
g cm
3
Sr = Vw / Vv = 65,69 cm / 91,82 cm
3
3
==>
Sr = Sr =
%
Fórmula alternativa: Sr = (γs*ω) / (γw*e) d) Sr = Vw / Vv = 0,95 Se supone que el Vv no cambia (el agua desplaza al aire)
3 3
Vwfin = Sr * Vv = 0,95 * 91,82 cm ==> Vwagreg = Vwfin - Vwini = (87,23 - 65,69) cm ==>
3
Vwfin =
87,23 Vwagreg =
cm
21,54
cm3
Mecánicade Suelos (64.08) - Trabajo Práctico Nº1
e) ω= ? ω = 87,23 g / 279,51 g ω =Ww / Ws ==> Wwfin= 87,23 ω= ω= Ejercicio 4 g 0,31 31 %
W pic+W w1 = W pic+W w2+Ws= Ws = a) γs = ?
281,6 320,3 62,1
g g g
W pic+W w1 ∆Vw = Vs
W pic+W w2+Ws
(Wpic+W w1)+ Ws - (Wpic+W w2+Ws) = 281,6g + 62,1g - 320,3g = ∆W w ==> ∆Vw = ∆W w / 1 (g/cm ) ∆Vw = Vs = γs = Ws / Vs γs = 62,1g / 23,4cm Ejercicio 5
33
23,4
cm
3
=>
γs =
2,65
g/cm3
Wh = ω= Vtot = γs = a) γd = ?
1790 0,198 945 2,69
g cm 3 g/cm
3
γd = Ws / Vtot
Ww = Ws * ω Ww = Wh - Ws
Ws * ω = Wh - Ws Ws * ( 1 + ω ) = Wh ==> Ws = Wh / ( 1 + ω ) = 1790g / ( 1+ 0,198) Ws = γd = 1494,16g / 945cm
3
1494,16 1,58
g g/cm3
=>
γd =
Mecánica de Suelos (64.08) - Trabajo Práctico Nº1
b) Sr = ? Ws= 1494,16 Sr = Vw / Vv g
3
==>
Vs = Ws / γs = 1494,16g / 2,69 (g/cm ) Vv = Vtot - Vs = ( 945 - 555,45 ) cm 295,84
3 3
3
cm y Vs = 555,45 3 cm Vv = 389,55 Ww = Ws * ω = 1494,16g * 0,198 = Sr = Vw / Vv = 295,84 cm / 389,55 cm
3
g
==> Sr = Sr =
Vw = 0,76 76 %
295,84
cm
3
==>
c) γh = ? Sr = 1
3
γh = Wh / Vtot = γs (1 + ω) / (1 + e) Sr = ω γs / (e γw) ==> e...
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