Investigacion

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  • Publicado : 25 de agosto de 2010
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8.1 .- ¿Cuál es la diferencia principal entre la alternativa independiente y mutuamente excluyente?

Primordialmente esta referido al condicionamiento física y económica.

a) La tasa de rendimiento es igual para la inversión que para financiamiento

b) Las tasas de rendimiento varían con forme varían los signos C + o – de los flujos de efectivo

8.2 .- Determina la tasa deretorno global de las siguientes inversiones

A) $50000 al 25% anual

B) $10000 al 40% anual

C) $ 40000 al 2% anual

D) $20000 al – 10% anual

25% 40% 2% -10%

2172 11449.182 3006.784 948.550

A) A= P (A/P, i, n)

= 50000 (A/P, i, n)

= 50000 (A/P, 25%, 4)

= 50000 (.42344)

= 21172B) A= P (A/P, i, n)

= 21172 (A/P, i, n)

= 21172 (A/P, 40%, 4)

= 21172 (.54077

= 11449.182

C) A= P (A/P, i, n)

= 11449.182 (A/P, i, n)

= 11449.182 (A/P,2%, 4)

= 11449.182 (.26262)

= 3006.784

D) A= P (A/P, i, n)

= 3006.784 (A/P, i, n)= 3006.784 (A/P, -10%, 4)

= 3006.784 (.31547)

= 948.550

8.3.- ¿Por qué es necesario comprar entre sí alternativas independientes?

Por la tasa de rendimiento que varían conforme a los signos que el darse uno de ellos "no condiciona" a que se dé el otro (esto es que si uno se cumple, no aumenta ni disminuye la probabilidad de que se dé el otro). P(A|B)= P(A)[pic]

MAQUINA P

Vp1=-$18000

Vp2= F(p/F,i,n)=$18000(p/F,6%,3)= $18000(0.8396)=-$15112.8

Vp3= F(p/F,i,n)=$18000(p/F,6%,6)= $18000(0.7050)=-$12690

Vp4= F(p/F,i,n)=$18000(p/F,6%,9)= $18000(0.5919)=-$10654.2

Vp5= F(p/F,i,n)=$18000(p/F,6%,12)= $18000(0.4970)=-$8946

Vp6= F(p/F,i,n)=$18000(p/F,6%,15)= $18000(0.4173)=-$7511.4

Vp7= F(p/F,i,n)=$18000(p/F,6%,18)=$18000(0.3503)=-$6305.4

Vp8= F(p/F,i,n)=$18000(p/F,6%,21)= $18000(0.2942)=-$5295.6

Vp9= F(p/F,i,n)=$18000(p/F,6%,24)= $18000(0.2470)=-$4446

Vp10= A(p/A,i,n)=$4000(p/F,6%,27)= $4000(13.2105)=-$52842

VPt=-$141803.4

Vp11= F(p/F,i,n)=$3000(p/F,6%,3)= $3000(0.8396)=$2518.8

Vp12= F(p/F,i,n)=$3000(p/F,6%,6)= $3000(0.7050)=$2115

Vp13= F(p/F,i,n)=$3000(p/F,6%,9)= $3000(0.5919)=$1775.7

Vp14=F(p/F,i,n)=$3000(p/F,6%,12)= $3000(0.4970)=$1491

Vp15= F(p/F,i,n)=$3000(p/F,6%,15)= $3000(0.4173)=$1251.9

Vp16= F(p/F,i,n)=$3000(p/F,6%,18)= $3000(0.3503)=$1050.9

Vp17= F(p/F,i,n)=$3000(p/F,6%,21)= $3000(0.2942)=$882.6

Vp18= F(p/F,i,n)=$3000(p/F,6%,24)= $3000(0.2470)=$741

Vp19= F(p/F,i,n)=$3000(p/F,6%,27)= $3000(0.2074)=$622.2

VPt=$12449.1

VPT=$12449.1-$141803.4

VPT=$-129354.3MAQUINA Q

Vp1=-$35000

Vp2= F(p/F,i,n)=$35000(p/F,6%,9)= $35000(0.5919)=$20716.5

Vp3= F(p/F,i,n)=$35000(p/F,6%,18)= $35000(0.3503)=$12260.5

Vp4= A(p/A,i,n)=$3600(p/F,6%,27)= $3600(13.2105)=$47557.8

Vpt=-$115534.8

Vp5= F(p/F,i,n)=$2500(p/F,6%,9)= $2500(0.5919)=$1479.75

Vp6= F(p/F,i,n)=$2500(p/F,6%,18)= $2500(0.3503)=$875.75

Vp7=F(p/A,i,n)=$2500(p/F,6%,27)= $2500(0.2074)=$518.5Vpt=$2874

VPT=$2874 - $115534.8

VPT=$-112660.8

[pic]

PROCESO E

Vp1=-$43000

Vp2= F(p/F,i,n)=$ 43000 (p/F,5%,4)= $43000 (0.8227)=-$35376.1

Vp3= F(p/F,i,n)=$ 43000 (p/F,5%,8)= $43000 (0.6768)=-$29102.3

Vp4= F(p/F,i,n)=$ 43000 (p/F,5%,12)= $43000 (0.5568)=-$23942.4

Vp5= F(p/F,i,n)=$ 43000 (p/F,5%,16)= $43000 (0.4581)=-$19698.3

Vp6= F(p/F,i,n)=$43000(p/F,5%,20)= $43000(0.3769)=-$16206.7

Vp7= F(p/F,i,n)=$43000(p/F,5%,24)= $43000(0.3101)=-$13334.3

Vp8= F(p/F,i,n)=$43000(p/F,5%,28)= $43000(0.2551)=-$10969.3

Vp10= A(p/A,i,n)=$10000(p/F,5%,32)= $10000(15.8027)=-$158027

Vp11= F(p/F,i,n)=$5000(p/F,5%,4)= $5000(0.8227)=$4113.5

Vp12= F(p/F,i,n)=$5000(p/F,5%,8)= $5000(0.6768)=$3384

Vp13= F(p/F,i,n)=$5000(p/F,5%,12)= $5000(0.5568)=$2784

Vp14=...
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