# Micr

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• Publicado : 2 de septiembre de 2012

Vista previa del texto
q = L1/2 k1/4 r = 1 P = 10 1 L-1/2 K1/4 - λ w = 0 2
W = 3
∂q∂L =

∂q∂K =
1 L1/2 K-3/4 - λ r = 04

λ = L1/2 K-3/4
λ = L-1/2 K1/4

Igualando λ
2 w
4 r

4 r
2 wL-1/2 K1/4 = L1/2 K-3/4

L1/2 4r K1/4
L1/2 = K-3/4 2 w

L K 4r
1 = 1 2w

2w
L = K 4r
L = 2 k r = 2 k (1) =k

k = 3 L /2
W 3
3
L = 2 k

Fk r
FL = w

L = 2/3 k
K = 3/2 L
2k = 3L
K= 2/3 Lq = L1/2 k1/4
q = L1/2 (3/2 L)1/4
q= L1/2 (3/2)1/4 L1/4
(1,5)1/4
q = L3/4

(1,5)1/4
L = q4/3

q= (2/3 k)1/2 k1/4
C = wL + rK
C = wL+ 1,5 L
C=4,5 L
C = 3 L + 1,5 L

C = 4,5 (q4/3/ 1,10668)
C = 4,066q4/3
Cma = P
5,42 q1/3= 10
q = 6,28
q1/3 = 1,845
q= 6,28
L = 10,453
Reemplazando :
(1,5)1/4
L =q4/3 L = 10,453

K = 15,679

K = 2L
K = 3 ( 10,453) / 2
WL = 3 ( 10,453) = 31,359
r k = 1 * ( 15,679) = 15,679
CT =47,038
I T = 10 * ( 6,28) = 62,8
∏= 62,8 – 47,038 = 15,762
VpmaL q k = 15,679

10,453 L L
q L = 10,453 Vmakk 15,679
Cma10
6,28 q