Mineria

Resistencia de materiales

B D F53
53
53
53

37
37

37
37
37
37
37
37




6
6

6
6

6
6

37
37
3737

53
53
53
53
53
53
53
53

Ax
H
H

A 4,5 cm C 4,5 cm E 4,5 cm G 4,5 cmHy
Hy
Ay60000

Reacciones en A y H

+ Σ M A= 0 = (60000) (9) = (Hy) – (18)=> (Hy) = ( 6000018) (9) = 30000 [Kg]

+ Σ M H = 0 = - (60000) (9) + (Ay) (18)=> (Ay) = ( 6000018) (9) = 30000 [Kg]

Comprobación +  Σ Fy = 0 =Ay + Hy – 60000 [Kg]30000 [Kg] + 30000 [Kg] – 60000 [Kg]

+ Σ FH = 0 = Ax


FUERZAS EN NUDO A: (AB)y = AB Sen(53º)

(AB)x AB+ Σ Fy = 0 = A+ (AB)y = 30000[Kg] + (ABy)


(AB)y => 30000[Kg]+ AB . Sen (53º)

AC => AB = 30000[Kg]Sen (53º) = 37564,07[Kg]

Ay



+ Σ Fx = 0 = AG + (AB)x (AB)x =...