Mineria
B D F53
53
53
53
37
37
37
37
37
37
37
37
6
6
6
6
6
6
37
37
3737
53
53
53
53
53
53
53
53
Ax
H
H
A 4,5 cm C 4,5 cm E 4,5 cm G 4,5 cmHy
Hy
Ay60000
Reacciones en A y H
+ Σ M A= 0 = (60000) (9) = (Hy) – (18)=> (Hy) = ( 6000018) (9) = 30000 [Kg]
+ Σ M H = 0 = - (60000) (9) + (Ay) (18)=> (Ay) = ( 6000018) (9) = 30000 [Kg]
Comprobación + Σ Fy = 0 =Ay + Hy – 60000 [Kg]30000 [Kg] + 30000 [Kg] – 60000 [Kg]
+ Σ FH = 0 = Ax
FUERZAS EN NUDO A: (AB)y = AB Sen(53º)
(AB)x AB+ Σ Fy = 0 = A+ (AB)y = 30000[Kg] + (ABy)
(AB)y => 30000[Kg]+ AB . Sen (53º)
AC => AB = 30000[Kg]Sen (53º) = 37564,07[Kg]
Ay
+ Σ Fx = 0 = AG + (AB)x (AB)x =...
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