practicas de topo

Páginas: 6 (1455 palabras) Publicado: 10 de marzo de 2014
TOPOGRAFÍA
PRÁCTICA 1



INTERSECCIÓN INVERSA





















Topografía
Índice

-Introducción………………………………………………………3

-Cálculo de Distancias.………………………..…….………..4

-Cálculo de Ángulos………………..……………….………….5

-Cálculo de Acimuts…………………………………………….6

-Cálculo de coordenadas…………….…….………………...7





Topografía
Cálculos

1.B Calcular Dr y ΔZ. Siendoi=1,65
Dr=G·sen2V G=100(Hs-Hi)
ΔZ=t+i-m t=tg·Dr α=100-obsV m=
1. obsV=103,8450 Hs=1375 Hi=0356
G = 100·(1375-0356) = 101900 mm = 101,9 m Dr = 101,9·Sen2 (103,8450) = 101,5287 m
α = 103,8450 – 100 = 3,8450g Tg (α) = t/Dr
t = 101,5287·tg (3,8450g) = - 6,1395 m m = (1,375 + 0,356)/2 = 0,8655 m
ΔZ = - 6,1395 + 1,65 – 0,8655 = - 5,355 m
2. obsV = 99,4620g. Hs = 0893 mm. Hi = 0236mm.

G = 100·(0893-0236) = 65700 mm = 65,7 m Dr = 65,7·Sen2 (99,4620) = 65,6953 m
Tg (V) = Dr/t t = Dr/ Tg (V) = 65,6953/ Tg (99,4620g)
t = 0,5551 m m = (0,893 + 0,236)/2 = 0,5645 m
3. obsV = 103,5685g. Hs = 2059 mm. Hi = 1569 mm.

G = 100·(2059-1569) = 49000 mm = 49 m Dr = 49·Sen2 (103,5685) = 48,8462 m
α = 103,5685 – 100 = 3,5685g Tg (α) = t/Dr
t = 48,8462·tg (3,5685g) = -2,7408 m m = (2,059 + 1,569)/2 = 1,814 m
ΔZ = - 2,7408 + 1,65 – 1,814 = - 2,9048 m
4. obsV = 98,6202g. Hs = 1058 mm. Hi = 0368 mm.

G = 100·(1058-0368) = 69000 mm = 69 m Dr = 69·Sen2 (98,6202) = 68,9676 m
Tg (V) = Dr/t t = Dr/ Tg (V) = 68,9676/ Tg (98,6202g)
t = 1,4950 m m = (1,058 + 0,368)/2 = 0,713 m
ΔZ = 1,4950 + 1,65 – 0,713 = 2,432 m
5. obsV = 100,6560g. Hs = 2125 mm. Hi= 0256 mm.

G = 100·(2125-0256) = 186900 mm = 186,9 m Dr = 186,9·Sen2 (100,6560) = 186,8801 m
α = 100,6560 – 100 = 0,6560g Tg (α) = t/Dr
t = 186,8801·tg (0,6560g) = - 1,9257 m m = (2,125 + 0,256)/2 = 1,1905 m
ΔZ = - 1,9257 + 1,65 – 1,1905 = - 1,4662 m
6. obsV = 99,5585g. Hs = 1125 mm. Hi = 0020 mm.

G = 100·(1125-0020) = 110500 mm = 110,5 m Dr = 110,5·Sen2 (99,5585) = 110,4946 m
Tg(V) = Dr/t t = Dr/ Tg (V) = 110,4946/ Tg (99,5585g)
t = 0,7663 m m = (1,125 + 0,020)/2 = 0,5725 m
ΔZ = 0,7663 + 1,65 – 0,5725 = 1,8438 m
7. obsV = 102,5680g. Hs = 1098 mm. Hi = 0256 mm.

G = 100·(1098-0256) = 84200 mm = 84,2 m Dr = 84,2·Sen2 (102,5680) = 84,0630 m
α = 102,5680 – 100 = 2,5680g Tg (α) = t/Dr
t = 84,0630·tg (2,5680g) = - 3,3927 m m = (1,098 + 0,256)/2 = 0,677 mΔZ = - 3,3927 + 1,65 – 0,677 = - 2,4197 m
8. obsV = 99,8256g. Hs = 1059 mm. Hi = 0268 mm.

G = 100·(1059-0268) = 79100 mm = 79,1 m Dr = 79,1·Sen2 (99,8256) = 79,0994 m
Tg (V) = Dr/t t = Dr/ Tg (V) = 79,0994/ Tg (99,8256g)
t = 0,2167 m m = (1,059 + 0,268)/2 = 0,6635 m
ΔZ = 0,2167 + 1,65 – 0,6635 = 1,2032 m
9. obsV = 100,4580g. Hs = 2224 mm. Hi = 1998 mm.

G = 100·(2224-1998) =22600 mm = 22,6 m Dr = 22,6·Sen2 (100,4580) = 22,5988 m
α = 100,4580 – 100 = 0,4580g Tg (α) = t/Dr
t = 22,5988·tg (0,4580g) = - 0,1625 m m = (2,224 + 1,998)/2 = 2,111 m
ΔZ = - 0,1625 + 1,65 – 2,111 = - 0,6235 m
10. obsV = 99,5680g. Hs = 2678 mm. Hi = 0045 mm.

G = 100·(2678-0045) = 263300 mm = 263,3 m Dr = 263,3·Sen2 (99,5680) = 263,2878 m
Tg (V) = Dr/t t = Dr/ Tg (V) = 263,2878/ Tg(99,5680g)
t = 1,7866 m m = (2,678 + 0,045)/2 = 1,3615 m
ΔZ = 1,7866 + 1,65 – 1,3615 = 2,0751 m
11. obsV = 105,7890g. Hs = 2001 mm. Hi = 1358 mm.

G = 100·(2001-1358) = 64300 mm = 64,3 m Dr = 64,3·Sen2 (105,7890) = 63,7697 m
α = 105,7890 – 100 = 5,7890g Tg (α) = t/Dr
t = 63,7697·tg (5,7890g) = - 5,814 m m = (2,001 + 1,358)/2 = 1,6795 m
ΔZ = - 5,814 + 1,65 – 1,6795 = - 5,8435 m
12.obsV = 98,5678g. Hs = 1578 mm. Hi = 0687 mm.

G = 100·(1578-0687) = 89100 mm = 89,1 m Dr = 89,1·Sen2 (98,5678) = 89,0549 m
Tg (V) = Dr/t t = Dr/ Tg (V) = 89,0549/ Tg (98,5678g)
t = 2,003 m m = (1,578 + 0,687)/2 = 1,1325 m
ΔZ = 2,003 + 1,65 – 1,1325 = 2,5205 m
13. obsV = 104,7850g. Hs = 2049 mm. Hi = 0987 mm.

G = 100·(2049-0987) = 106200 mm = 106,2 m Dr = 106,2·Sen2 (104,7850) =...
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