Proyecto motores acplados

Solo disponible en BuenasTareas
  • Páginas : 4 (994 palabras )
  • Descarga(s) : 0
  • Publicado : 17 de agosto de 2012
Leer documento completo
Vista previa del texto
UNIVERSIDAD TECNOLOGICA DE NOGALES SONORA





MECATRONICA



SISTEMAS DE CONTROL AUTOMATICO



PROYECTO MOTORES ACOPLADOS


ALONSO ROMO BORBÓN


EDWIN LOPEZ RIVAS


GABRIELGOMEZ DUARTE


ING. ÁLVARO VELARDE


3¨F¨




H. NOGALES, SONORA 10 DE AGOSTO DEL 2012



voltaje RPM
0 0
0.25 0
0.50 0
0.75 0
1 0
1.25 0
1.50 0.16
1.75 0.19
20.37
2.25 0.41
2.50 0.45
2.75 0.45
3 0.47
3.25 0.60
3.50 0.70
3.75 0.76
4 0.78
4.25 0.79
4.50 0.80
4.75 0.82
5 0.84



















Ts=.120 seg
ع= 0.5
m=(Y2-Y1)/(X2-X1)
B= 1/m=1/0.206=4.854
J=(B*ts)/5=((4.854)(0.120seg))/5=0.116


(ω(s))/j(s) =1/(js+B)=(1/j)/(js/j+4.854/0.116)=(1/0.116)/(█(s+@)41.84)

(ω(s))/(v(s))=8.620/(s+41.84)

Paso#1(ω(s))/(v(s))=(8.620/(s+41.84)(KDS+KP+KI/S))/(1+8.620/(s+41.84) (KDS+KP+KI/S) )

Paso#2
(ω(s))/(v(s))=((8.620(KDS+KP+KI/S))/(s+41.84))/((1+8.620(KDS+KP+KI/S)/(s+41.84))

Paso#2b
1/1+(8.620(KDS+KPKI/S))/(s+41.84)
(s+41.84+8.620(KDS+KP KI/S))/(s+41.84)

Paso#3
(ω(s))/(v(s))=((8.620(KDS+KP KI/S))/(s+41.84))/((s+41.84+8.620(KDS+KP KI/S))/(s+41.84))

Paso#4
(ω(s))/(v(s))=(8.620(KDS+KPKI/S))/(s+41.84+8.620(KDS+KP+KI/S))
Paso#4b
S(KDS+KP+KI/S)= (KDS^2+KPS+KI)/S

Paso#5
(8.620(KDS+KP KI/S))/((s+41.84)/1+(8.620(KDS+KP+KI/S))/S)
Paso#5b
(ω(s))/(v(s))=(8.620(KDS+KPKI/S))/((s+41.84)/1+8.620(KDS+KP+KI/S)/S)
(S^2+41.84+8.620(KDS^2+KPS+KI))/S

Paso#6
(ω(s))/(v(s))=((8.620(KDS^2+KPS+KI))/S)/((S^2+41.84+8.620(KDS^2+KPS+KI))/S)

Paso#7(ω(s))/(v(s))=(8.620(KDS^2+KPS+KI))/(S^2+41.84+8.620(KDS^2+KPS+KI))

Paso#8
(ω(s))/(v(s))=(8.620KDS^2+8.620KPS+8.620KI)/(S^2+41.84+8.620(KDS^2+KPS+KI))

Paso#9
(ω(s))/(v(s))=(8.620KDS^2+8.620KPS+8.620KI)/(S^2+(1+8.620KD)+S(41.84+8.620KP)+8.620KI)(C(s))/(R(s))=(ωn^2)/(S^2+2ع ωnS+ωn^2 )
ts=0.120
ع=0.5
n=6/عts=6/((0.5)(0.120))=6/0.06=100

(C(s))/(R(s))=(100)^2/(S^2+2(0.5)(100)S+(100)^2 )

(C(s))/(R(s))=10,000/(S^2+100S+10,000)...
tracking img