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2° TRABAJO DE ESTATICA

ALUMNO: CONDORI TITO HERNAN DAVID
1. HALLAR LAS REACCIONES

15010,8,4-(0,8,0)116f(x)=150(10)116= 139.27

f(z)=150(4)116= 55.71

20010,8,0-(10,0,4)80

f(y)=200(8)80= 178.88

f(z)=200(-4)80= -89.4435010,0,4-(0,0,0)116

f(x)=350(10)116= 324.97

f(z)=350(4)116= 129.99

∑Fx=0
Rx + 324.97 + 139.27 = 0
Rx = -464.24

∑Fy = 0
Ry +178.88 = 0
Ry = -178.88

∑Fz = 0
55.71 + 129.99 – 89.44 – Rz = 0
-96.26 = Rz

2. HALLAR LAS REACCIONES15010,7,4-(0,7,0)116

f(x)=150(10)116= 139.27

f(z)=150(4)116= 55.71

20010,7,0-(10,0,4)65

f(y)=200(7)65= 173.65

f(z)=200(-4)65=-99.23

35010,0,4-(0,0,0)116

f(x)=350(10)116= 324.97

f(z)=350(4)116= 129.99

∑Fx=0
Rx + 139.27 + 324.97 = 0
Rx =-464.24

∑Fy = 0
Ry + 173.65 = 0
Ry = -173.65

∑Fz = 0
55.71 – 99.23 + 129.99 - Rz = 0
-86.47 = Rz

3. HALLAR LASREACCIONES

∑Fx=0
Rx – 128.05 + 128.05 = 0
Rx = 0

∑Fy = 0
Ry + Ry – 100 – 150 – 350 + 2(153.63) - 150 = 0
2Ry = 442.74
Ry= 221.37

4. HALLAR LOS MOMENTOS Mx,My,Mz

Mx = Fydz + Fzdy
Mx = 173.66 (4) + 557.22 (4)
Mx = 2923.52

My = Fxdz +Fzdx
My = 208.01 (4) – 477.62 (4) – 318.41 (6)
My = -2988.9

Mz = Fxdy + Fydx
Mz = 557.22 (6) + 75.93 (6)
Mz = 3798.9
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