# Tacnologia

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• Publicado : 1 de junio de 2010

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PRIMER CIRCUITO

RTAB:

IT:

PROCEDIMIENTO MATEMATICO

RA= R1+R2= 0.68k+4.7k=5.38k
RB=R4+R5= 1K+O.47K=1,47K
RC=R6+R7= O.22K+O.68K=0.9K
RD=1/R8+1/R9+1/R10=1/10K+1/6.8K+1/4.7K=2.17K

RE= 1/2.2K+1/1.47K= O.881K

RTAB= 5.38+O.881+0.9+O.47= 9.8K

RESISTENCIAS | R(KΩ) | VOLTAJE (V) | CORRIENTE (mA) |
R1 | 0.68 | 1.38 | 2.04 |
R2 | 4.7 | 9.58 | 2.04 |R3 | 2.2 | 1.79 | 0.813 |
R4 | 1 | 1.22 | 1.22 |
R5 | O.47 | 0.573 | 1.22 |
R6 | 0.22 | 1.83 | 2.O4 |
R7 | 0.68 | 1.83 | 2.04 |
R8 | 10 | 4.42 | 0.442 |
R9 | 6.8 | 4.42 |0,650 |
R10 | 4.7 | 4.42 | 0.940 |
R11 | 0.47 | 0.95 | 2.04 |

Con la anterior grafica podemos comprobar todo lo que se pedía al inicio del circuito.

SEGUNDO CIRCUITORTAB=

IT=

PROCEDIMIENTO MATEMATICO

RA=4.7K+6.8K+1K= 12.5K
RB=1K+O.47K=1.47K
RC=2.2K+3.3K=5.5K
RD=O.22K+O.68K=0.9
RE=1/10K+1/6,.8K +1/4.7K=2,17K

RF=1/2.2K+1/1.47K=O.881KRG=.O881+0.9=1.78

RH=1/1.78+1/5.5=1.34K

RI=4.7+1.34+2.17=8.74

RJ=1/12.5+1/8.74=5.15K

RTAB=O.68K+5.14+0.47K=6.29K

RESISTENCIAS | R(KΩ) | VOLTAJE(V) | CORRIENTE(mA) |R1 | 0.68k | 1.61V | 2.36mA |
R2 | 4.7k | 6.69V | 1.42mA |
R3 | 2.2k | 1.55V | 0.70mA |
R4 | 1k | 2.38V | 2.38mA |
R5 | 0.47k | 1.11V | 2.36mA |
R6 | 0.22k | 0.52V | 2.36mA |R7 | 0.68k | 1.61V | 2.36mA |
R8 | 10k | 3.09V | 0.30mA |
R9 | 6.8k | 3.09V | 0.45mA |
R10 | 4.7k | 3.09V | 0.65mA |
R11 | 0.47k | 1.13V | 1.04mA |
R12 | 4.7k | 4.6V | 0.97mA|
R13 | 6.8k | 6.65V | 0.97mA |
R14 | 1k | 2.38V | 2.38mA |
R15 | 2.2k | 3.18V | 1.44mA |
R16 | 3.3k | 1.46V | 0.44mA |

INFORME DE CIRCUITOS Y LABORATORIO

JOHAN STIVENPEREZ FLOREZ
CODIGO: 210171055
ANDRERS HERRERA
CODIGO:

JORGE CORREDOR
PROFESOR

ESCUELA COLOMBIANA DE CARRERAS INDUSTRIALES

ELECTRONICA INDUSTRIAL

MARZO 13

2010