Tareas

Páginas: 4 (812 palabras) Publicado: 9 de febrero de 2013
MATRICES DE INTERNET
Dadas las matrices:

C1=(2)(1)+(0)(1)+(1)(1)= 2+0+1= 3
C12=(2)(0)+(0)(2)+(1)(1)= 0+0+1= 1
C13=(2)(1)+(0)(1)+(1)(0)= 2+0+0= 2
C21=(3)(1)+(0)(1)+(0)(1)= 3+0+0= 3C22=(3)(0)+(0)(2)+(0)(1)= 3+0+0= 3
C23=(3)(1)+(0)(1)+(0)(o)= 3+0+0= 3
C31=(5)(1)+(1)(1)+(1)(1)= 5+1+1= 7
C32=(5)(0)+(1)(2)+(1)(1)= 5+2+1= 8
C33=(5)(1)+(1)(1)+(1)(0)= 5+1+1= 7
C= 3 1 2
33 3
7 8 7

www.vitutor.com/algebra/matrices/m_e.html
Dadas las matrices:
A= 1 2 3 B= -1 5 -2
-1 0 22 2 -1
3 1 2
C1=(1)(-1)+(2)(2)+(3)(3)= -1+4+9= 12
C12=(1)(5)+(2)(2)+(3)(1)= 5+4+3= 12
C13=(1)(-2)+(2)(-1)+(3)(2)= -2+-2+6=2C21=(-1)(-1)+(0)(2)+(2)(3)= 1+0+6= 7
C22=(-1)(5)+(0)(2)+(2)(1)= -5+0+2= -3
C23=(-1)(-2)+(0)(-1)+(2)(2)= 2+0+4= 6

C= 12 12 2
7 -3 6www.Im.ucv.d/hipertexto/alineal/cap1/ejers.html

A= 1 0 B= 2 2
3 2 0 5

C1=(1)(2)+(0)(0)= 2+0= 2
C12=(1)(2)+(0)(5)=2+0 = 2C21=(3)(2)+(2)(0)= 6+0= 6
C22=(3)(2)+(2)(5)= 6+10= 16

C= 2 2
10 16

http://www.monteroespinosa.com/fotos/resueltos/solucion_10402101.gifEJERCICIO MULTIPLICACION DE MATRICES
(Libro) Algebra Lineal con Aplicaciones Gareth Williams
Pagina47
A= 1 3B= 5 0 1
2 0 3 -2 6

C1=(1)(5)+(3)(3)= 5+9= 14
C12=(1)(0)+(3)(-2)= 0+-6= -6
C13=(1)(1)+(3)(6)= 1+18= 19
C21=(2)(5)+(0)(3)= 10+0=10
C22=(2)(0)+(0)(-2)= 0+0= 0
C23=(2)(1)+(0)(6)= 2+0= 2

C =...
Leer documento completo

Regístrate para leer el documento completo.

Estos documentos también te pueden resultar útiles

  • Tareas tareas y mas tareas
  • tareas tareas
  • Taran Taran
  • tareas tareas
  • Tareas Y Tareas
  • Mis tareas...Tus tareas
  • Tareas de Tareas
  • Tareas

Conviértase en miembro formal de Buenas Tareas

INSCRÍBETE - ES GRATIS