# Termodinamica

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• Publicado : 23 de febrero de 2011

Vista previa del texto
ECUACION DE REDUCH KWONG
P= R (T) _ a (T)
v-b ( v) (v+b)
Dónde:
P=Presión
a= 9.34x10-4 m3
b=1.01x10-6 m3
v= volumen constante 63.61m3
R= constante de gas
Aire 0.2870KPa*m3/k
Helio 2.0769 Kpa*m3/k
Calcular (a)
a= 27 (0.870 KPa*m3/K)2 (132.5K)2
64 (3770 KPa)2
a= 9.34x10-4 m3
Calcular (b)
b= (0.870KPa*m3/K) (132.5K)(8) (3770KPa)2
b= 1.01x10-6 m3
Cálculos para 20°C=293.14K
Aire
P= (0.287KPa*m3/k) (293.14K) _ (9.34x10-4 m3) (293.14K)
(63.61m3 – 1.01x10-6 m3)(63.61m3) (63.61m3 + 1.01x10-6 m3)
P= 1.3226 – 6.76x10-5
P= 1.3225 KPa

Helio
P= (2.0769KPa*m3/k) (293.14K) _ (9.34x10-4m3) (293.14K)
(63.61m3 – 1.01x10-6m3) (63.61m3)(63.61m3 + 1.01x10-6 m3)
P= 9.5711 – 6.76x10-5
P= 9.5710 KPa
Cálculos para 30°C=303.14K
Aire
P= (0.287KPa*m3/k) (303.14K) _ (9.34x10-4m3) (303.14K)
(63.61m3 – 1.01x10-6m3)(63.61m3) (63.61m3 + 1.01x10-6 m3)
P= 1.3677 – 6.99x10-5
P= 1.3676 KPa
Helio
P= (2.0769KPa*m3/k) (303.14K) _ (9.34x10-4m3) (303.14K)
(63.61m3 – 1.01x10-6m3)(63.61m3) (63.61m3 + 1.01x10-6 m3)
P= 9.8976 – 6.99x10-5
P= 9.8975 KPa
Cálculos para 40°C=313.14K
Aire
P= (0.287KPa*m3/k) (313.14K) _ (9.34x10-4m3) (313.14K)
(63.61m3 –1.01x10-6m3) (63.61m3) (63.61m3 + 1.01x10-6 m3)
P= 1.4128 – 7.22x10-5
P= 1.4127 KPa

Helio
P= (2.0769KPa*m3/k) (313.14K) _ (9.34x10-4m3) (313.14K)
(63.61m3 – 1.01x10-6m3)(63.61m3) (63.61m3 + 1.01x10-6 m3)
P= 10.2241 – 7.22x10-5
P= 10.2240 KPa
Cálculos para 50°C=323.14K
Aire
P= (0.287KPa*m3/k) (323.14K) _ (9.34x10-4m3) (323.14K)(63.61m3 – 1.01x10-6m3) (63.61m3) (63.61m3 + 1.01x10-6 m3)
P= 1.4579 – 7.45x10-5
P= 1.4578 KPa
Helio
P= (2.0769KPa*m3/k) (323.14K) _ (9.34x10-4m3) (323.14K)
(63.61m3 –...