Trabajo de diseño

DATOS
3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
5 | 5 | 4 | 3 | 2 | 4 | 6 | 7 |
6 | 6 | 6 | 8 | 5 | 3 | 7 | 8 |
7 | 7 | 7 | 9 | 6 | 4 | 9 | 3 |
8 | 9 | 6 | 3 | 7 | 5 | 2 | 1 |
9 | 10 | 5 | 2 | 6 |6 | 4 | 5 |

| REPLICAS | TOTAL | MEDIA |
TRATAMIENTOS | I | II | III | IV | V | VI | VII | VIII | | |
A | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 52 | 8,6 |
B | 5 | 5 | 4 | 3 | 2 | 4 | 6 | 7 |36 | 6 |
C | 6 | 6 | 6 | 8 | 5 | 3 | 7 | 8 | 49 | 8,1 |
D | 7 | 7 | 7 | 9 | 6 | 4 | 9 | 3 | 52 | 8,6 |
E | 8 | 9 | 6 | 3 | 7 | 5 | 2 | 1 | 41 | 6,8 |
F | 9 | 10 | 5 | 2 | 6 | 6 | 4 | 5 | 47 |7,8 |
| | | | | | | | | 277 | |

DISEÑO COMPLETAMENTE AL AZAR

DIAGRAMA DE CAMPO
TRATAMIENTOS | I | II | III | IV | V | VI | VII | VIII |
A | 5 | 5 | 4 | 6 | 2 | 6 | 10 | 9 |
B |3 | 5 | 7 | 2 | 1 | 6 | 8 | 9 |
C | 7 | 9 | 6 | 3 | 4 | 7 | 9 | 7 |
D | 3 | 8 | 8 | 7 | 6 | 5 | 6 | 6 |
E | 4 | 7 | 5 | 6 | 3 | 4 | 2 | 5 |
F | 3 | 8 | 7 | 6 | 9 | 4 | 5 | 10 |

ANALISIS DEVARIANZA
F.V | G.L | S.C | C.M | F.CAL | F.TAB 5% | F.TAB1% |
TRATAMIENTO | 5 | 25,85 | 5,17 | 1,003 | 2,44 | 3,49 |
ERROR | 42 | 216,63 | 5,15 | | | |
TOTAL | 47 | 242,48 | | | | |F. Correlación = (Total Tratamiento)2N 277248= 1598,52
G. L. Tratamiento = N – 1 6 – 1= 5
G. L. Error = Total – Tratamiento 47 – 5 = 42
G. L. Total = N – 1 48 –1= 47
S.C. Tratamiento= ∑(TotalTratamiento2)N– F.Correlacion =522+362+492+522+412+4728-1598,52 = 25,85
S. C. Total = (Total)2 – F. Correlación = 32+42+52+62+72……+52– 1598,52
S. C. Total =1841 –1598,52 = 242,48
S. C. Error = S.C Total –S.C Tratamiento = 242,48 –25,85 = 216.63
C. M. Tratamiento = S.C.Tratamiento G.L.Tratamiento= 25,855= 5,17
C. M. Error = S. C.ErrorG.L.Error=216,6342=5,15

F. Calculada = C.M.TratamientoC.M.Error=5,175,15= 1.003
T=Tratamientos*C.M. ErrorR
T=6*5,158
T=30,98
T=0,69
N = 48 N – 2 = 46
T. Tabulada al 5% = 1,67
T. Tabulada al 1% =...