# Trabajo

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• Publicado : 9 de diciembre de 2010

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CICLOS |
Elemento | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | ƩX | X | CAL.ACT. | T.N. |
Trazar suela | 23 | 18 | 15 | 16 | 19 | 17 | 16 | 17 | 17 | 16 | 15| 17 | 16 | 17 | 17 | 18 | 18 | 19 | 311 | 17.27 | 96% | 16.5792 |
Recortar suela | 82 | 78 | 78 | 78 | 79 | 75 | 73 | 77 | 78 | 85 | 81 | 79 | 79 | 79 | 76 | 83 | 78 | 80 | 1418 | 78.77 | 95% |74.8315 |
Operación 1.- Trazar y recortar suela.

TRAZAR SUELA.
F.A.= CAL. ACT/100= 96/100=0.96
T.N.=(F.A)(MEDIA)=(0.96)(17.27)=16.5792
T.S=T.N(1+TOLERANCIA/100)=16.5792(1+10/100)=18.237RECORTAR SUELA.
F.A.= CAL. ACT/100=95/100=0.95
T.N.=(F.A)(MEDIA)=(0.95)(78.77)=74.8315 h/p
T.S=T.N(1+TOLERANCIA/100)=74.8315(1+10/100)=82.314 h/p

T.S. TOTAL=0.0167585
T.N. TOTAL=0.015235
Operación 2.- Trazar y recortar correa.

CICLOS |
Elemento | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | ƩX | X | CAL.ACT | T.N. |
Trazar correa | 19 | 20 | 21 | 24 | 18 | 22.5 | 19 | 20 | 20| 16 | 199.5 | 19.95 | 80% | 15.8 |
Recortar correa | 181 | 169 | 162 | 181 | 181 | 179 | 139 | 144 | 151 | 154 | 1641 | 164.1 | 75% | 123.075 |

TRAZAR CORREA.
F.A.= CAL. ACT/100= 80/10=0.80T.N.=(F.A)(MEDIA)=(0.80)(19.75)=15.8 h/p.
T.S=T.N(1+TOLERANCIA/100)=15.8(1+10/100)=17.38 h/p.
RECORTAR CORREA
F.A.= CAL. ACT/100=75/100=0.75
T.N.=(F.A)(MEDIA)=(0.75)(164.1)=123.075 h/p.T.S=T.N(1+TOLERANCIA/100)=123.075(1+10/100)=135.325 h/p.
T.N TOTAL = 0.0231458 h/p. T.S TOTAL = 0.0254508 h/p.
Operación 3.- Trazar y recortar plantilla.

CICLOS |
Elemento | 1 |2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 |
Trazar plantilla | 20 | 20 | 24 | 21 | 24 | 23 | 25 | 21 | 25 | 20 | 21 | 22 | 25 | 21 | 24 | 23 | 25| 23 | 21 | 20 | 21 | 20 |
Recortar plantilla | 60 | 60 | 63 | 62 | 63 | 65 | 64 | 66 | 63 | 60 | 59 | 64 | 65 | 66 | 60 | 65 | 60 | 65 | 59 | 60 | 61 | 60 |
ƩX | X | CAL.ACT | T.N. |
489 |...