alimentacion en el deporte


CÁLCULO TÍPICO


Cálculo del calor cedido por el vapor:

Para un caudal de 0.2 pie3/min:

m = ( 110 ml * 1 g/ml * 1/5s * 0.0022lb/1g * 3600s/1h = 174.24 lb/h

Q = 174.24 lbm/h *(1142.26 – 50.08 ) Btu/lbm
Q = 190301.44 Btu/h


Para un caudal de 0.3 pie3/min:

m = ( 130 ml * 1 g/ml * 1/5s * 0.0022lb/1g * 3600s/1h = 205.92 lb/h

Q = 205.92 lbm/h* (1140.82 – 50.08 ) Btu/lbm
Q = 224605.18 Btu/h


Para un caudal de 0.4 pie3/min:

m = ( 150 ml * 1 g/ml * 1/5s * 0.0022lb/1g * 3600s/1h = 237.6 lb/h

Q = 237.6 lbm/h * (1135.88 – 50.08) Btu/lbm
Q = 257986.08 Btu/h


Para un caudal de 0.5 pie3/min:

m = ( 160 ml * 1 g/ml * 1/5s * 0.0022lb/1g * 3600s/1h = 253.44 lb/h

Q = 253.44 lbm/h * (1128.58– 50.08 ) Btu/lbm
Q = 273335.04 Btu/h








Cálculo del calor absorbido por el agua:


Para un caudal de 0.2 pie3/min:

m = (0.2 pie3/min * 1g/ml * 60min/1h *28316.85ml/1pie3 *0.0022lb/1g
m = 747.56 lb/h


Qa = ( 747.56 lbm/h * 4.179 KJ / Kg* 0C * ( 93 – 28 ) 0C * 1000J/1KJ *
9.486x10-4 BTU/1J * 0.4536Kg/1lb)
Qa = 87375.15 Btu/h


Paraun caudal de 0.3 pie3/min:

m = (0.3 pie3/min * 1g/ml * 60min/1h *28316.85ml/1pie3 * 0.0022lb/1g
m = 1121.35 lb/h


Qa = ( 1121.35 lbm/h * 4.179 KJ / Kg* 0C * ( 91 – 28 ) 0C * 1000J/1KJ *9.486x10-4 BTU/1J * 0.4536Kg/1lb)
Qa = 127031.16 Btu/h


Para un caudal de 0.4 pie3/min:

m = (0.4 pie3/min * 1g/ml * 60min/1h *28316.85ml/1pie3 * 0.0022lb/1g
m =1495.13 lb/h


Qa = ( 1495.13 lbm/h * 4.179 KJ / Kg* 0C * ( 82 – 28 ) 0C * 1000J/1KJ *
9.486x10-4 BTU/1J * 0.4536Kg/1lb)
Qa = 145178.15 Btu/h



Para uncaudal de 0.5 pie3/min:

m = (0.5 pie3/min * 1g/ml * 60min/1h *28316.85ml/1pie3 * 0.0022lb/1g
m = 1868.91 lb/h


Qa = ( 1868.91 lbm/h * 4.177 KJ / Kg* 0C * ( 76 – 28 ) 0C * 1000J/1KJ *...