Cálculo De Armaduras De Acero

2m

Área de la nave industrial
Nota: La estructura estará a cada 4m a lo largo de la nave.
24m

A) 1 y 3 2 y 4
A=b*h2 A=B+b2*h
A= 1m² A= 3 m²
13

2 4
Cálculo de las áreas tributarias.
4m

16m

2m

(Kg./m²)
FIGURA | ÁREA | CARGA MUERTA | CARGA VIVA | CARGA FIJA |
1 | 1 | 19.322 | 40 | 95.0508 |2 | 3 | 57.966 | 120 | 285.1524 |
3 | 1 | 19.322 | 40 | 95.0508 |
4 | 3 | 57.966 | 120 | 285.1524 |

* Carga muerta (C.M.)= (lamina galvanizada en 3 ft de ancho) calibre 12=19.322 kg/m
* Carga viva (C.V.)= 40kg/m²
* Carga fija (C.F.)= 1.7 C.V. + 1.4 C.M.
De tal forma tenemos que W= ∑C.F. / Área. W=760.4064 /8= 95.0508Kg.

285.1524kg.

w= 71.2881 Kg/m4m

R₁= 142.5762 Kg. Mmáx. = (-71.2881)(x)(x/2) + (142.5762)(x)
R₂= 142.5762 Kg. Mmáx (4m) = 0

2 4
1
3
3

2 4
1W₁= 71.2881 Kg/m
W₂= 71.2881 Kg/m
∑ 142.5762 Kg/m = 1.425762 Kg/cm.

396.8432 kg.
Ahora bien tenemos que: PERFIL: 100 x 8.32

2 4
1
3
12 4
( 8.32Kg.)(4)= 33.28 kg.

285.1524kg
3
95.0508 kg.
396.8432 kg.
∑ 380.2032kg. 380.2032 kg / 2 = 190.1016 kg.
16.64kg. 16.64kg.
∑ 396.8432 kg. ∑ 206.7416 kg.

* BARRAS:

1595.693 kg. (C) = RS, AB.
1964.274kg. = BC (T), CD (C) PQ (C), QS (T).
1403.053 = DE (T), EF (C), NO (C), OP (T).
841.832 = FG(T), GH (C) LM (C), MN (T).
280.611 = HI (T), IJ (C), JK (T), KL (C)
2,777.903 = CE (T), OQ (T)
4,762.188 = EG (T), MO (T)
5,952.648 = GI (T), KM (T)
6,349.491 = IK (T)
0 = AC, QR
1,388.951 =PS (C), BD (C)
3,770.010 = NP (C), DF (C)
5,357.383 = LN (C), FH (C)
6,151.070 = JL (C), HJ(C)

* REACCIONES:
Ay= 1438.990 kg.
Ky= 1438.990 KG.

DATOS |
  |   |
d= | 50.80 |
tw= |...