calculos cele2

mAl= masa del aluminio (en g)
VF =Volumen de agua fría (en ml)
tagua = temperatura del agua fría (en °C)
tAl=temperatura del aluminio (en °C)
teq=temperatura en equilibrio (en °C)
43.2 g
200 ml22°C
23°C
----

Temperatura (t) del sistema °C
(t)
Cp
23°C
0
4.874
33°C
2:26
4.906
43°C
4:15
4.938
53°C
6:16
4.970
63°C
8:27
5.003
73°C
11:02
5.035
83°C
14:10
5.067
92°C
17:15
5.096

CALCULOS1.-Conversiones °C-K
K=273.15+°C
K=273.15+22°C=295.15 K
K=273.15+23°C=296.15 K
K=273.15+33°C=306.15 K
K=273.15+43°C=316.15 K
K=273.15+53°C=326.15 K
K=273.15+63°C=336.15 K
K=273.15+73°C=346.15 KK=273.15+83°C=356.15 K
K=273.15+92°C=365.15 K
2.-Calculo Cp
CP-del Aluminio=4.80+0.00322(296.15 K)=5.7536 cal/K*mol
CP-del Aluminio=4.80+0.00322(306.15 K)=5.7858 cal/K*mol
CP-del Aluminio=4.80+0.00322(316.15 K)=5.8180cal/K*mol
CP-del Aluminio=4.80+0.00322(326.15 K)=5.8502 cal/K*mol
CP-del Aluminio=4.80+0.00322(336.15 K)=5.8824 cal/K*mol
CP-del Aluminio=4.80+0.00322(346.15 K)=5.9146 cal/K*mol
CP-delAluminio=4.80+0.00322(356.15 K)=5.9468 cal/K*mol
CP-del Aluminio=4.80+0.00322(365.15 K)=5.9757 cal/K*mol
3.-Calculo Cp media
Cpm=(( CP Al1+ CP Al2)/2=(5.7536+5.7858)/2=5.7697 cal/K*mol
Cpm=(( CP Al2+ CPAl3)/2=(5.7858+5.8180)/2=5.8019 cal/K*mol
Cpm=(( CP Al3+ CP Al4)/2=(5.8180+5.8502)/2=5.8341 cal/K*mol
Cpm=(( CP Al4+ CP Al5)/2=(5.8502+5.8824)/2=5.8663 cal/K*mol
Cpm=(( CP Al5+ CP Al6)/2=(5.8824+5.9146)/2=5.8985cal/K*mol
Cpm=(( CP Al6+ CP Al7)/2=(5.9146+5.9468)/2=5.9307 cal/K*mol
Cpm=(( CP Al7+ CP Al8)/2=(5.9468+5.9757)/2=5.96125 cal/K*mol
Cpm=(( CP Al8+ CP Al1)/2=(5.9757+5.7536)/2=5.86465 cal/K*mol
4.-Calculo n
n=m/PM
n=43.2g/(27g/mol)=1.6mol
5.- Calculo Calor Suministrado (Q)
Q=nCpΔT
Q=(1.6mol)( 5.7697 cal/K*mol)( 306.15 K-296.15 K)= 92.3152 cal
Q=(1.6mol)( 5.8019 cal/K*mol)( 316.15 K-306.15 K)= 92.8304cal
Q=(1.6mol)( 5.8341 cal/K*mol)( 326.15 K-316.15 K)= 93.3456 cal
Q=(1.6mol)( 5.8663 cal/K*mol)( 336.15 K-326.15 K)= 93.8608 cal
Q=(1.6mol)( 5.8985 cal/K*mol)( 346.15 K-336.15 K)= 94.376 cal...