Calculos De Columnas

DISEÑO DE COLUMNA DE P.A. INTERIOR (C1-PA)
Carga ultima de diseño
Pu= 196129 + (2120) (35.35) + 1.2 (.35 x .35 x 2400)
Pu= 270,362kg

Ac= 270,362÷177.8= √1520.5cm² = 38.99 ≈ 40x40cms
KLrx=.65400.3040= 21.66<34
As= ᶴbd
As= (0.2)(40)(40)= 32cm²/3.88= 8 #7
Sep Est.
16ØL= 16(2.23)= 35.68√
48ØT= 48(0.95)= 45.6
dmin= 40
EST. 38" @35cms
Calculo de la capacidad admisible a compresionPadm. = Ø[0.85(200)(40x40) + (8 x 3.88 x 4200)]
Padm= 281658 > Pu= 270362kg

DISEÑO DE COLUMNA DE P.B. INTERIOR (C1-PB)
Carga ultima de diseño
Pu= 270362 + (2120) (35.35) + 1.2 (.35 x .35 x2400)
Pu= 345,027kg

Ac= 345,027kg÷177.8= √1941cm² = 44.05 ≈ 45x45cms
KLrx= .65400.3045= 19.26<34
As= ᶴbd
As= (0.2)(45)(45)= 40.5cm²/5.07= 8 #8
Sep Est.
16ØL= 16(2.54)= 40.64√
48ØT=48(0.95)= 45.6
dmin= 45
EST. 38" @40cms
Calculo de la capacidad admisible a compresion
Padm. = Ø[0.85(200)(45x45) + (8 x 5.07 x 4200)]
Padm= 360,221 > Pu= 345,027kg

CALCULO DEL AREA DE ACERO DELPEDESTAL (P-1)

As= ᶴbd
As= (0.2)(50)(50)= 50cm²/5.07= 10 #8
Sep Est.
16ØL= 16(2.54)= 40.64√
48ØT= 48(1.27)= 60.96
dmin= 50
EST. 11" @40cms
Calculo de la capacidad admisible a compresionPadm. = Ø[0.85(200)(50x50) + (10 x 5.07 x 4200)]
Padm= 446,558 > Pu= 360,221

DISEÑO DE COLUMNA DE 3er NIVEL PERIMETRAL (C2-3N)
Carga ultima de diseño
Pu= (1432) (24.53)
Pu= 35,127kg

Ac=35127÷177.8= √197.6cm² = 14.06 ≈ 25x25cms
-> Rige seccion y armado minimo (sec. 25x25cms EST. 3/8" @ 20cms)
KLrx= .65400.3025= 34.66<34 No pasa
Propone sec. 30x30cms
KLrx= .65400.3030=28.89<34√

As= ᶴbd
As= (0.02)(30)(30)= 18cm²/1.98= 9 #5
Sep Est.
16ØL= 16(1.57)= 25.12√
48ØT= 48(0.95)= 45.6
dmin= 30
EST. 38" @25cms
Calculo de la capacidad admisible a compresion
Padm. =Ø[0.85(200)(30x30) + (9 x 1.98 x 4200)]
Padm= 160,020kg > Pu= 35,127kg

DISEÑO DE COLUMNA DE 2do NIVEL PERIMETRAL (C2-2N)
Carga ultima de diseño
Pu= 35,127 + (2120) (24.53) + 1.2 (.3 x .3 x 4...