Calculos de evaporador efecto simple
Tanques Diámetro (cm)
Altura (cm) en Tiempo de ( 5min ) Altura (cm) en Tiempo de ( 5min ) Altura (cm) en Tiempo de ( 5min )
1ra Corrida 2da Corrida 3ra Corrida
Talimentación
59.6 4.9 4.8 4.9
T vapor de caldera
40.2 3.6 3.2 3.9
T producto concentrado 34.6 10.7 10.6 10.6
T evaporado condensado 34.6 3.8 3.7 3.6
Datos de Tanque Agua de EnfriamientoTiempo Altura Diámetro
20 seg 6.5 cm 56 cm
Tabla de Temperaturas
T1 T2 T3 T4 T5
112 ºC 74 ºC 74 ºC 34 ºC 32 ºC
Datos de Operación
Rotámetro 20%
P calandria 0.7 Kg/cm2
T calandria 60 ºCP vacio 31 cm Hg
CALCULOS DEL EVAPORADOR DE SIMPLE EFECTO
M_A1=(π*D^2*∆h*ρ)/4ө=(π(0.596m)^2 (0.049m)(1000 kg/〖cm〗^3 ))/(4(0.083h))=164.7 kg/h
M_A2=(π*D^2*∆h*ρ)/4ө=(π(0.596m)^2 (0.048m)(1000kg/〖cm〗^3 ))/(4(0.083h))=161.34 kg/h
M_A3=(π*D^2*∆h*ρ)/4ө=(π(0.596m)^2 (0.049m)(1000 kg/〖cm〗^3 ))/(4(0.083h))=164.7 kg/h
M_P=(π*D^2*∆h*ρ)/4ө=(π(0.346m)^2 (0.106m)(1000 kg/〖cm〗^3))/(4(0.083h))=120.079 kg/h
E=(π*D^2*∆h*ρ)/4ө=(π(0.346m)^2 (0.037m)(1000 kg/〖cm〗^3 ))/(4(0.083h))=41.91 kg/h
M_V=(π*D^2*∆h*ρ)/4ө=(π(0.102m)^2 (0.032m)(1000 kg/〖cm〗^3 ))/(4(0.083h))=48.93 kg/h
MA=MP+E161.34kg/h = (120.08+41.91)kg/h
161.34kg/h =161.99kg/h
W=(π*D^2*∆h*ρ)/4ө=(π(0.560m)^2 (0.065m)(1000 kg/〖cm〗^3 ))/(4(5.55X〖10〗^(-3) h))=192.88 kg/h
CALOR TRANSFERIDO
QT = EHE + MPHP + MAHA
HP =CpT
HP = (1 Kcal/(Kg°C))(74°C)=74 Kcal/Kg
HA= (1 Kcal/(Kg°C))(64°C)=64 Kcal/Kg
QT = (41.91 kg/h) (628.9 Kcal/Kg) +(120.08 kg/h)(74 Kcal/Kg)+ (164.7 kg/h )(64 Kcal/Kg)
QT=24702.3Kcal/h
CALORSUMINISTRADO
QS = MVλ_V
Qs=(48.93 kg/h)(531.3 Kcal/h)=25996.5 Kcal/h
AREA DE TRANSFERENCIA DE CALOR
A= π NT D h
A= π*4(3X〖10〗^(-3) m)(2.54m) = 0.095m
EFICIENCIA TERMICA
ŋ=Q/Qs=(24702.3 Kcal/h)/(25996.5 Kcal/h) =0.95(100) = 95%
Capacidad de transferencia de calor
CQ=QT/A=(24702.3 Kcal/hr)/(0.095 m2)=260024.21 kcal/hrm2
Coeficiente Global de Transferencia de Calor...
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