Capitulo Secto Ley Federal Del Trabajo
Física (y) | 82 | 78 | 86 | 72 | 91 | 80 | 95 | 75 | 89 | 74 |
x | y | xy |x2 | y2 | y1 | (y- y1)2 |
75 | 82 | 6150 | 5625 | 6724 | 78.64 | 11.29 |
80 | 78 | 6240 | 6400 | 6084 | 81.74 | 13.99 |
93 | 86 | 7998 | 8649 | 7396 |89.8 | 14.44 |
65 | 72 | 4680 | 4225 | 5184 | 72.44 | 0.19 |
87 | 91 | 7917 | 7569 | 8281 | 86.08 | 24.21 |
71 | 80 | 5680 | 5041 | 6400 | 76.16 |14.74 |
98 | 95 | 9310 | 9604 | 9025 | 92.9 | 4.41 |
68 | 75 | 5100 | 4624 | 5625 | 74.3 | 0.49 |
84 | 89 | 7476 | 7056 | 7921 | 84.22 | 22.85 |
77 | 74| 5698 | 5929 | 5476 | 79.88 | 34.57 |
798 | 822 | 66249 | 64722 | 68116 | 816.16 | 141.2 |
m=nxy-x ynx2-x2m=1066249-798(822)10(64722)2-7982
m=662490- 655956647220-636804 m=65410416
m=0.62
b=x2y-x xynx2-x2 b=(64722)(822)-(798)(66249)(10)(64722)-(798)2b=33478210416 b=32.14
ECUACIÓN DE AJUSTE OPTIMO
y=mx+b
y=0.62x+32.14
Si el alumno obtuviera 90 puntos de algebra su puntaje físico será de 87. 94x=90
y=0.62(90)+32.14
y=87.94
Si el alumno obtuviera 73 puntos en algebra su puntaje físico será 77.4
x=73
y=0.62(73)+32.14
y=77.4x=y-bm
y=68
x=68-32.140.62
x=57.33
y=79
x=79-32.140.62
x=75.58
ERROR ESTANDAR DE AJUSTE
Syx=y-y12n-2Syx=(141.2)210-2
Syx=19937.48
Syx=49.92
r=nxy-xynx2-x2ny2-y2
r=1066249-798(822)10647220-(798)21068116-(822)2
r=662490-655956102.05-74
r=65347551.7
r=0.86
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