Destilacion Radioactiva

Páginas: 7 (1585 palabras) Publicado: 15 de julio de 2012
1. Caso 1 reactor semicontinuo sin destilación reactiva

EN POLYMATH
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Calculated values of DEQ variables
| Variable | Initial value | Minimal value | Maximal value | Final value |
1 | t | 0 | 0 | 120. | 120. |
2 | Na | 300. | 150.9916 | 300. | 150.9916 |
3 | Nb | 0 | 0 | 210.9916 | 210.9916 |
4 | Nc | 0 | 0 | 149.0084 | 149.0084 |
5 | Nd| 0 | 0 | 149.0084 | 149.0084 |
6 | T | 350. | 350. | 350. | 350. |
7 | Cb0 | 5. | 5. | 5. | 5. |
8 | Fb0 | 3. | 3. | 3. | 3. |
9 | v00 | 0.6 | 0.6 | 0.6 | 0.6 |
10 | v0 | 150. | 150. | 150. | 150. |
11 | Kc | 0.6986285 | 0.6986285 | 0.6986285 | 0.6986285 |
12 | k | 1.669907 | 1.669907 | 1.669907 | 1.669907 |
13 | V | 150. | 150. |222. | 222. |
14 | Ca | 2. | 0.6801426 | 2. | 0.6801426 |
15 | Cb | 0 | 0 | 0.9504128 | 0.9504128 |
16 | Cc | 0 | 0 | 0.6712088 | 0.6712088 |
17 | Cd | 0 | 0 | 0.6712088 | 0.6712088 |
18 | ra | 0 | -0.0187594 | 0 | -0.0025899 |
19 | x | 0 | 0 | 0.4966945 | 0.4966945 |

Differential equations
1 | d(Na)/d(t) = ra * V |
2 | d(Nb)/d(t) = ra* V + Fb0 |
3 | d(Nc)/d(t) = -ra * V |
4 | d(Nd)/d(t) = -ra * V |

Explicit equations
1 | T = 350 |
2 | Cb0 = 5 |
3 | Fb0 = 3 |
4 | v00 = Fb0 / Cb0 |
5 | v0 = 150 |
6 | Kc = 5.2 * exp((-8000 / 1.987) * ((1 / 298) - (1 / T))) |
7 | k = (8.88 * (10 ^ 8)) * exp(-7032.1 / T) |
8 | V = v0 + v00 * t |
9 | Ca = Na / V |
10 | Cb = Nb / V |
11 | Cc =Nc / V |
12 | Cd = Nd / V |
13 | ra = -k * (Cb * Ca - (Cc * Cd / Kc)) |
14 | x = (300 - Na) / 300 |

Grafica de concentración vs tiempo

Grafica de velocidad de reacción vs tiempo

2. Caso 2 reactor semicontinuo con destilación reactiva, solo se evapora el acetato de metilo.

EN POLYMATH

Calculated values of DEQ variables
| Variable | Initial value | Minimal value |Maximal value | Final value |
1 | t | 1.0E-08 | 1.0E-08 | 120. | 120. |
2 | Na | 300. | 11.45134 | 300. | 11.45134 |
3 | Nb | 0 | 0 | 71.45134 | 71.45134 |
4 | Nc | 0 | 0 | 4.592267 | 1.741388 |
5 | Nd | 0 | 0 | 288.5487 | 288.5487 |
6 | V | 150. | 150. | 199.5029 | 199.5029 |
7 | T | 350. | 350. | 350. | 350. |
8 | Ca | 2. | 0.0576053| 2. | 0.0576053 |
9 | Cb | 0 | 0 | 0.3576725 | 0.3576725 |
10 | Cc | 0 | 0 | 0.0297592 | 0.0087479 |
11 | Cd | 0 | 0 | 1.446323 | 1.446323 |
12 | Kc | 0.6986285 | 0.6986285 | 0.6986285 | 0.6986285 |
13 | k | 1.669907 | 1.669907 | 1.669907 | 1.669907 |
14 | Fb0 | 3. | 3. | 3. | 3. |
15 | Cb0 | 5. | 5. | 5. | 5. |
16 | v00 | 0.6 | 0.6| 0.6 | 0.6 |
17 | Mwc | 74. | 74. | 74. | 74. |
18 | De | 943.4 | 943.4 | 943.4 | 943.4 |
19 | Pc | 4750. | 4750. | 4750. | 4750. |
20 | Pt | 101.3 | 101.3 | 101.3 | 101.3 |
21 | Ft | 100. | 100. | 100. | 100. |
22 | Xc | 0 | 0 | 0.0149842 | 0.0046772 |
23 | Tc | 506.5 | 506.5 | 506.5 | 506.5 |
24 | ra | 0 | -0.0193037 | 0 |-0.004164 |
25 | Tr | 0.6910168 | 0.6910168 | 0.6910168 | 0.6910168 |
26 | Pv1 | 0.041342 | 0.041342 | 0.041342 | 0.041342 |
27 | Pvc | 196.3743 | 196.3743 | 196.3743 | 196.3743 |
28 | Fc | 0 | 0 | 2.904743 | 0.9066899 |
29 | x | 0 | 0 | 0.9616968 | 0.9616968 |

Differential equations
1 | d(Na)/d(t) = ra * V |
2 | d(Nb)/d(t) = ra * V + Fb0 |
3 |d(Nc)/d(t) = -(ra * V) - Fc |
4 | d(Nd)/d(t) = -ra * V |
5 | d(V)/d(t) = v00 - ((Fc * Mwc) / De) |

Explicit equations
1 | T = 350 |
2 | Ca = Na / V |
3 | Cb = Nb / V |
4 | Cc = Nc / V |
5 | Cd = Nd / V |
6 | Kc = 5.2 * exp((-8000 / 1.987) * ((1 / 298) - (1 / T))) |
7 | k = (8.88 * (10 ^ 8)) * exp(-7032.1 / T) |
8 | Fb0 = 3 |
9 | Cb0 = 5 |
10 | v00...
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