Dinamica,Movimiento Relatibo,Resorte,Cantidad De Movimiento

2x=y a)

2(.6m)=y=1.2m

2vx=vy

U1-2=(150N)(.6)-(3Kg)(9.81 )(1.2m)=90Nm-35.319Nm=54.684Nm V1=0 T2= T2= U1-2=T2 T1=0 + + =6 +4 =10 =5.684 =2.3384

54.684Nm=10Kg d

b) Posición 1U1-2=150(d)-3(9.81)(y)=150d-(29.43)(2d)=150d-58.86d=91.14d V1=0 T2= U1-2=T2 T1=0 = =4 + =10 =9.114d Ángel Alberto Carvajal Pool

91.14d=10

Posición 2 X=.6-d y=1.2-2dU2-3=150(.6-d)-3(9.81)(1.2-2d)=90-150d-35.316+58.86d=54.684-91.14d U2-3=T2 Como 54.684-91.14d=10 5.4684-9.114d= entonces

=9.114d y 5.4684-9.114d=

5.4684-9.114d=9.114d 5.4684=18.228d d=.3m

=3-9+F=0 =6-Kx=6-8x =0 T1=0 U1-2 U1-2=T2F=9-3 F=6

T2= -9x=6x-4 -9x=-3x-4

-3x-4x2=

Cuando la velocidad es máxima la aceleración ( ) es cero 2v =- (3+8x)=0 3+8x=0 8x=-3 x=-3/8

Sustituyendo x en -3x-4x2= -3(-3/8)-4(-3/8)2= v2=( - )= v= =1.1073

Ángel Alberto Carvajal Pool

V=0

T 1=

U1-2=-mg(x)

V2=0

T2=0

-mg(x)=0 =g(x) X=13047910.3ft ( =(x) x= =13047910.3ft

)=2471.195 millas

Altura máxima=60millas+247.195 millas=2531.195 millas

a) ra=3j+k ma=1kg rb=3i+2.5k mb=2kg rc=4i+2j+k mc=3kg

(1kg+2kg+3kg) = ma*ra + mb*rb + mc*rc (6kg) =1kg(3j+k)+2kg (3i+2.5k) +3kg(4i+2j+k) (6kg)=(3j+k)+(6i+5k)+(12i+6j+3k) (6kg) =18i+9j+9k =3i+1.5j+1.5k b) va=3i-2j+4k ma*va=3i-2j+4k mb*vb=8i+6j mc*vc=6i+15j-9k Ángel Alberto Carvajal Pool vb=4i+3j vc=2i+5j-3k

m =ma*va+mb*vb+mc*vc=(3i-2j+4k)+(8i+6j)+(6i+15j-9k)=(17i+19j-5k)

c) rag=ra- =(3j+k)-( 3i+1.5j+1.5k)=-3i+1.5j-.5k rbg=rb- =(3i+2.5k)-( 3i+1.5j+1.5k)=-1.5j-k rcg=rc- =(4i+2j+k)-( 3i+1.5j+1.5k)=i+.5j-.5k HG= rag× ma*va+ rbg ×mb*vb +rcg ×mc*vc HG=HG=(5i+10.5j+1.5k)+(-6i+8j+12k)+(3i+6j+12k)=(2i+24.5j+25k)

mv0=mava+mbvb+mvb mv0-mvb=mava+mbvb

va=7.5ft/s vb=5ft/s

m=(3/4 oz)(1libra/16 oz)=3/64 oz(3/64)(v0)=(4)(7.5)+(10)(5)+(3/64)(5)=80.2343 V0=80.2343(64/3)=1711.666ft/s mv0=mv1+mava (3/64)(1711.666)=(3/64)v1+(4)(7.5) 80.32-30=(3/64)v1 50.2343(64/3)=v1 T0=( T1=( )= )+ =( v1=1071.666666 =2135.52 J )+ =(225+53834.5045)/2g=839.4333107J...