diseño de losas

Planta baja- dimensiones 3x4.4

h= 1320/250= 5.28cm.
WD= 240(.1)=240kg/cm2
WL= 150kg/cm2
Concreto =2400kg/cm2
W= 1.4(240)+1.7(150)=591kg/cm2
a1/a2 = 3/4.4 = .68 ~ 0.7

M= (130)10-4(591)(4.4)2 = 148.74
M= (371)10-4 (591)(4.4)2 = 424.48
M= (228)10-4 (591)(3)2 = 121.27
M= (432)10-4 (591)(3)2 = 429.78

Diseño p/ 148.74
14874 = 0.9(100)(10)2(170)q(.05q)
14874 = 1530000q(.05q2)14874/ 1530000 = q(.05q2)
0.5q2 –q + .0097 = 0
X= -(-1) +- (-1)2 -4(0.5)(.0097)
2 (.05)

X1 = 1+.99 = 1.99
1
X2 = 1-.99 = -0.01
1

P =-0.01(170) = .00040
4200
As= .00040(100)(10) = 0.40

Diseño p/ 424.48
42448 = 0.9(100)(10)2(170)q(.05q)
42448 = 1530000q(.05q2)
42448/ 1530000 = q(.05q2)
0.5q2 –q + .027 = 0
X= -(-1)+- (-1)2 -4(0.5)(.027)
2 (.05)

X1 = 1+.97 = 1.97
1
X2 = 1-.97 = 0.03
1

P = .03(170) = .0001
4200
As= .0001(100)(10) = 1.21Diseño p/ 121.27
12127 = 0.9(100)(10)2(170)q(.05q)
12127 = 1530000q(.05q2)
12127 / 1530000 = q(.05q2)
0.5q2 –q + .0079 = 0
X= -(-1) +- (-1)2 -4(0.5)(.0079)
2(.05)

X1 = 1+.99 = 1.99
1
X2 = 1-.99 = -0.01
1

P = -0.01(170) = .00040
4200
As= .00040(100)(10) = 0.40



Diseño p/ 229.78
22978 =0.9(100)(10)2(170)q(.05q)
22978 = 1530000q(.05q2)
22978/ 1530000 = q(.05q2)
0.5q2 –q + .015 = 0
X= -(-1) +- (-1)2 -4(0.5)(.015)
2 (.05)

X1 = 1+.97 = 1.97
1
X2 = 1-.97= 0.03
1

P = .03(170) = .0001
4200
As= .0001(100)(10) = 1.21

Corto y largo
As(-) = 0.40
As(+) = 1.21
1#3
S = 100/1 = 100cm
Smàx = 3(10) = 30cm

Acero p/temperatura
P = 0.0016
As = 0.0016 (10)(100) =1.6
3vrs #3
S= 100/ 3= 33.33cm
V = wl = 591(3) = 886.5kg
2 2
V = wl = 591(4.4) = 1300.2kg
2 2

VCR = 0.5FRbd...