Ecuaciones Diferenciales
2.- y’’+4y=0……(1) y= A cos 2x+ B sen 2x……(2)
Comprobación.
y’= -2 A sen 2x+ 2 B cos 2x….(3)
y’’= - 4 A cos 2x - 4 B sen 2x….(4)
Sustituir 4 y 2 en 1.
-4 A cos 2x – 4 B sen 2x + 4 (A cos 2x + B sen 2x)
-4 A cos2x – 4 B sen 2x + 4 A cos 2x + 4 B sen 2x = 0
Por lo tanto es solución 0 = 0
4. - y’’’= 6…. (1)y=x3 + ax2 + bx + c…….. (2)
Comprobación. Sustituir (5) en (1)
y’= 3x2 + 2ax + b…..(3) 6 = 6
y’’= 6x + 2a………(4)
y’’’= 6…………(5)
6.- y’= sen x…. (1) (usando el método de separación de variables)Comprobación.
[pic]= sen x [pic] y= - cos x +c
dy= sen x dx….(2) y= - cos x +c y’= - (cos x+c)
y’= - (-sen x)
Sustituir (3) en (1)y’= sen x…..(3)
sen x = sen x
10.- y’ + y = 0…. (1) y= ce-x …..(2)
Comprobación sustituimos 3 y 2 en 1
y= ce-x - ce-x + ce-x = 0
y’= - ce-x …..(3) 0 = 0
12.- xy’ – 4y = 0…. (1)y = cx4…..(2)
Comprobación sustituimos 4 y 2 en 1
y = cx4…..(3) 4cx3 – 4(cx4) = 0
y´= 4cx3….(4)
y’’=12 cx2….(5)
y’’’= 24cx…(6)
16.- y’=1; y= y (7) = 0; y= x+c comprobación
0 = 7 + c y = x + c
c = -7y’= 1
18.- [pic]
[pic] [pic] =[pic]
y[pic]=[pic]
y[pic]=2[pic]
y=[pic]+[pic]
y= 2 + C[pic]
Pagina 29.
6.- y’= cos y
[pic]
[pic]
[pic]= [pic]
In /sec y + tan y /= x + C
sec y + tan y= [pic]= [pic]
sec y + tan y=[pic] solución general
8.- [pic]
[pic]
[pic]
y[pic] [pic]u=x dv=[pic]
du=dx v=-[pic] [pic]
y[pic]= [pic] [pic] [pic] dx+C
y[pic]= - [pic] [pic] - [pic] [pic] + C
y= C[pic]- [pic] x - [pic] solución general
10.- [pic]
seau=[pic]+[pic]
u´=2x+2y y´
y=[pic]
u´- 2x =2 yu
u´-2yu= 2x [pic] = [pic]
u´[pic] = 2 [pic] dx + C
u´[pic] =- x u´[pic] + [pic] [pic] + C
[pic]= [pic] - [pic] + C
[pic]= - [pic] - + [pic] + C [pic] solución general
12.- 4y´+ y = 0
4 [pic]= -y
4 [pic]=- dx
4 [pic]= - [pic]
4 /In y / =-x + C/In [pic]/ =-x + C
[pic]=[pic] = [pic] = [pic]
[pic]
y=[pic] y=[pic] solucion general.
14.- y´+[pic]=0
[pic]
[pic]= - dx
[pic] = - [pic]
- [pic]= -x +C por (-1)
[pic]
1= Cx+ Cy
y= [pic]
Pagina 35.
6. - xy´+by=o
x[pic]+=-by
[pic] = - [pic]
[pic] = - b [pic]
In /y/ =-b /In x/ + In /c/
In /y/=In /[pic] / + In /c/In /y/ = In / C [pic]
y= C[pic] solucion general
8. - (x + 2) y´- xy = 0
(x + 2) [pic] - xy = o multiplicar por ( [pic] )
( [pic] ) [pic] * [pic] - [pic] = 0
[pic] - [pic] = 0
[pic]- [pic] = 0 [pic] - x -2 = 1 - [pic]
[pic] dx = 0
In /y/ - x + 2 In / x + 2 /= C=
In /y/ + In /x+ 2 /[pic]= x + C
Y(x+2)2...
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