Ejercicio de sistemas coordenados

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Universidad de Sonora

SISTEMAS COORDENADOS

Geometría Analítica
Prof. Pablo Ibarra Sagasta
Grecia González Navarro

Hermosillo Sonora a; lunes 30 deagosto del 2010.

(12,72.63º) (12,72.63º) = (3.5, 11.4)
B (8,11)
(5,302º) = (2.6, -4.2)

F (0,6) (7. 192.5º) = (-6.8,-1.51)
A (4,5)
C (-6,3) (3,111º) = (-1, 2.8)
(3,111º)

G (-4,0)
(7,192.5º) E (7,-2)

D (-4,-4) (5,302º)

dAB = √(8-4)² +(11-5)² = √16+ 36 = √52 = 7.2
dAC = √(-6 -4)² + (3-5)² = √100+4 = √104 = 10.9
dAD =√(-4-4)² + (-4-5)² = √64+81 = √145 = 12.04
dAE= √(7-4)² + (-2-5)² = √9+49 = √58 = 7.6
dAF = √(0-4)² + (6-5)² = √16 + 1 = √17 = 4.1
dAG = √(-4-4)² + (0-5)² =√64+25 = √89 = 9.4
dBC= √(-6-8)² + (3-11)² = √196 + 64 =√260 =16.1
dBD = √(-4-8)² + (-4-11)² = √144+225 = √369 =19.2
dBE = √(7-8)² + (-2-11)² = √ 1+81 = √82 = 9dBF = √(0-8)² + (6-11)² = √ 64 + 25 = √89 = 9.4
dBG = √(-4-8)² + (0-11)² = √ 144 + 121 = √265 = 16.5
dCD = √ (-4-6)² + (-4-3)² = √ 100+49= √149 = 12.2
dCE = √(7+6)² + (-2-3)² = √ 169 +25 = √194 = 13.9
dCF = √(0+6)²+(6-3)² = √ 36+9 = √45 = 6.7
dCG = √(-4+6)²+(0-3)² = √4+9 = 0√13 =3.6
dDE = √ (7+4)²+(-2+4)² = √11+4=√15 =3.8
dDF = √(0+4)²+(6+4)² = √16+100 = √ 116 =10.7
dDG = √(-4+4)²+(0+4)² =√0+16 = √16= 4
dEF = √(0-7)² +(6+2)² = √49+64 = √113 = 10.6
dEG = √(-4-7)+(0+2)² = √121+4 =√125 = 11.1
dFG = √(-4-0)²+(0-6)² = √16+36 = √52 = 7.2