Ejercicios De Calculo Vectorial

INSTITUTO POLITECNICO NACIONAL

ESCUELA SUPERIOR DE INGENIERIA MECANICA Y ELECTRICA
UNIDAD CULHUACAN

“EJERCICIOS DE LIBRO (CALCULO VECTORIAL, MARSDEN),(CALCULO, LEITHOLD)”ALUMNO: Hermenegildo Bello Alan



GRUPO: 2EV4

MATERIA: CALCULO VECTORIAL

PROFESOR: RAMIREZ SANCHEZ JOSE ADOLFO

FECHA DE ENTREGA: 24 ABRIL DE 2012

CALCULO,LEITHOLD
EJERCICIOS 11.1



* EN LOS EJERCICIOS 1 A 8 DETERMINAR EL DOMINIO DE LA FUNCION VECTORIAL




Dom Rt=t|-1≤t≤1



Dom Rt=R\{1}Dom Rt=(-1, 1]



Dom Rt=[-1, 1]


Dom Rt=-2,0∪(π,4]


Dom Rt=-∞,-3∪(3,∞)










(F+G)t=2ti+t2j+2t k
(F-G)t=2i+(t2-2)j+2 k
F∙Gt=3t3-3
F XGt=
=t3+t2-2ti-4tj-(t3-t2-2t) k


F+Gt=4i+t2j+(t2-8)k
F-Gt=(4-2t2)i+(8-t2)j+t2k
F∙Gt=4t2-t4
F X Gt=-32t3+8t2-t4i+(t4-8t2+16)j+(4t2-t4-16) kF+Gt=(cost+sent)i+(-sent cost)j
F-Gt=(cost-sent)i+sent cost+2tk
F∙Gt=-t2
F X Gt=tsent-tcosti+tsent+tcostj+k



F+Gt=2secti+(t-2)k
F-Gt=2tanj-(t+2)k
F∙Gt=-2t+1
(F X G)(t)=(ttant-2tant)i-(tsect+2sect)j-(2sect tant)k




fFt=t2-1i+t3-t2-t+1j+t2-2t+1k
fGt=t2-2t+1i+t-1j+t2-1k
F∘Gt=t+2i+t2+2tj+tk
G∘F=ti+j+t+2k


fFt=2+ti+22-tj-2+tkfGt=t22-ti-t+2j+24t-2k
F∘Gt=4t-t2i+4j-(4t-t2k
G∘F=t2-4t+4i+t2-2tj-4k




fFt=sent costi-sen2tj+tsentk
fGt=sen2ti+sentcostj-tsentk
F∘Gt=1-t2i+tj+sen-1tk
G∘F=ti+1-t2j-sen-1tkfF=i+sentj-2costk
fGt=i-sentj-tcostk

F∘Gt=1ti-1-t2tj-2k
G∘F=1ti-1-t2tj+cos-1tk


limt→-1Rt=-3i+2j-k

limt→-1Rt=-2i

limt→-1Rt=j+k


limt→-1Rt=j+klimt→-1Rt=-i+π2j+πk


limt→-1Rt=2i+2j




limt→-1Rt=-2i

limt→-1Rt=i+k




sol⟹(1,2)∪(2,∞]










sol⟹{t≠0,1}...