Ejercicios

670 N


2

2

1.5 1.5 1.5 1.5

∑ FX= 0 + ∑ MA= 0
AX= 0 -670 (3) + HY (6)= 0
∑ FY= 0 +HY= 335
AY + HY – 670 = 0
AY + HY = 670
AY= 670 – 335
AY= 335
RESOLUCION POR MEDIO DE NODOS:
NODO A:
FBA
0 FCA335
∑ FX= 0 +
O – FCA – Sen 0.8 = 0
FCA= - O.0140 (C)
∑ FY= 0 +
335 – FBA Cos 0.6 = 0
FBA= 335.0184 (T)
NODO B:
FDB



335.0184 FEB
0

∑ FX= 0 +
335.0184 Sen 0.8 +FDB Sen 0.8 + FEB Sen 0.8 = 0
FDB Sen 0.8 + FEB Sen 0.8 = - 4.67
∑ FY = 0 +
335.0184 Cos 0.6 – FDB Cos 0.6 + FEB Cos 0.6 = 0
- FDB Cos 0.6 + FEB Cos 0.6 = - 335
0.0139 FDB + 0.0139 FEB = - 4.67(0.9999)
- 0.9999 FDB + 0.9999 FEB = - 335 (0.0139)
0.0276 FEB = - 9.326
FEB = - 337.89 (C)
0.0139 FDB + 4.696 = - 4.67
FDB = - 4.67 – 4.6960.0139
FDB = - 673.81
NODO C:
673.81

0.0140 FCE


∑ FX= 0 +
0.0140 Sen 0.8 – FCE Sen 0.8 = 0
FCE = 0.00019
Sen 0.8FCE = 0.014 (T)
NODO D:





673.81 FFD
FED

∑ FX = 0 +
673.81 Sen 0.8 + FFD Sen 0.8 = 0
FFD = -9.407
Sen 0.8
FFD = - 673.74 (C)
∑ FY = 0 +673.81 Cos 0.6 + 673.74 Cos 0.6 + FED Cos 0.6 = 0
FED = - 9.407 – 673.70
Cos 0.6
FED = - 683.14 (C)
NODO E:
683.14337.89 FEF
0.014 FEG

∑ FY = 0 +
337.89 Cos 0.6 – 683.14 Cos 0.6 + FEF Cos 0.6 = 0
FEF = - 337.87 + 683.10Cos 0.6
FEF = 345.24 (T)
∑ FX = 0 +
0.014 Sen 0.8 – FEG Sen 0.8 + 345.24 Sen 0.8 + 337.89 Sen 0.8 = 0
FEG = - 0.00019 – 4.717 – 4.82
Sen 0.8
FEG = 683.05 (T)...