Estadistica

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PROCEDIMIENTOS
Problema
En la siguiente tabla se tienen las edades de los 100 ancianos que habitan un asilo público en la ciudad del carmen. Se quiere conocer paraobtener un mejor juicio acerca del tipo de servicio que requieren.

Obtención de datos
|62 |64 |68 |
|Clase 1 |53 |60|
|Clase 2 |61 |67 |
|Clase 3 |68 |74 |
|Clase 4 |75 |81|
|Clase 5 |82 |88 |
|Clase 6 |89 |95 |
|Clase 7 |96 |102|

Limites reales
LRIn = (LS n-1 + LIn) /2
LRI1 = (52 + 53 ) /2
LRI1 = 52.5

LRSn = (LSn +LIn+1) / 2
LRS1 = (60 + 61) /2
LRS1 = 121 /2
LRS1 = 60.5
LRIn = (LS n-1 + LIn) /2
LRI2= (60 + 61 ) /2
LRI2 = 60.5

LRSn = (LSn +LIn+1) / 2
LRS2 = (67 + 68) /2
LRS2 = 135 /2
LRS2= 67.5

LRIn = (LS n-1 + LIn) /2
LRI3 = (67 + 68 ) /2
LRI3 = 67.5

LRSn = (LSn +LIn+1) / 2
LRS3= (74 + 75) /2
LRS3 = 149 /2
LRS3= 74.5

LRIn = (LS n-1 + LIn) /2
LRI4 = (74 + 75 ) /2
LRI4 = 74.5

LRSn = (LSn +LIn+1) / 2
LRS4 = (81 + 82) /2
LRS4 = 163 /2
LRSn= 81.5

LRIn = (LS n-1+ LIn) /2
LRI5 = (81 + 82 ) /2
LRI5 = 81.5

LRSn = (LSn +LIn+1) / 2
LRS5 = (88 + 89) /2
LRS5 = 177 /2
LRS5 = 88.5

LRIn = (LS n-1 + LIn) /2
LRI6 = (88 + 89 ) /2
LRI6 = 88.5

LRSn = (LSn+LIn+1) / 2
LRS6 = (95 + 96) /2
LRS6 = 191 /2
LRS6= 95.5

LRIn = (LS n-1 + LIn) /2
LRI7 = (95 + 96 ) /2
LRI7 = 95.5

LRSn = (LSn +LIn+1) / 2
LRS7 = (102 + 103) /2
LRS7 = 205 /2
LRS7= 102.5Promedio

Xn= LI + LS /2
X1 = (53 + 60) /2
X1 = 113 / 2
X1 = 56.5

Xn = LI + LS /2
X2 = (61 + 67) /2
X2 = 128 / 2
X2 = 64

Xn = LI + LS /2
X3 = (68 + 74) /2
X3 = 142 / 2
X3 = 71...