Estadistica

ESTADISTICA II

1.
S = | 20P2 = | 20! | = | 380 | |
| | (20-2)! | | | |
2.
6! = | 720 |

3.
6*4*3*2 = | 144 | Formas diferentes |

4.
El espacio maestral de los 3 dadoses: |
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S = | (6)3 = | 216 | | |
5.
| N= 8 | |

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| 5 Técnicos |
| 3 Tecnólogos |
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comité = | 3 Técnicos |
|1 Tecnólogo |
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| 5 P3 * 3P1 = | 180 |

6
A = Despegue a Tiempo P(A) = 83% |
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B = Llegada a Tiempo P(B) = 82% |
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P(AyB) = 78% | | |
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a) P(B/A) = | 0,78/0,83 = | 0,9398 | |
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b) P(A/B) = 0,78/0,82 | 0,9512 | |

7.
n = 450 Lanzamiento de dos dados |
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P = 10/36 | | |
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E=450*(10/36) =125 | | |
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8.
S = [1,2,3,4,5,6] | |
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a) A = Par = [2,4,6] | |
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b) B = Mayores a 3 = [4,5,6] |
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P(A) =3/6 | |
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P(B) = 3/6 ||
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P(AyB) = 2/6 | |

9.
10 C4 = 210 | Sub Grupos de 4 |

10.
s = [CC, CS, SC, SS] | | |
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Xi = | cantidad de cosas observadas |
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a) | Xi |0 | 1 | 2 |
| P(Xi) | 1/4 | 1/2 | 1/4 |
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b) Construir el histograma | | |

11.
2P1 (3 - 1)! (4 - 1)! (4 - 1)! (2 - 1)! = 72

12.
a) 7 P4 * 4P2 = | 10080 |
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b)7 P3 * 4P3 = | 5040 |

13.
A = Despegue a Tiempo |
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P(A) = 89% | | |
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B = Llegue a Tiempo | |
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P(B) = 82% | | |
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P (A ^ B) = 48% | |
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a) P (B/A) = 0,48/0,89 = | 0,539326 |
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b) P(A/B) = 0,48/0,82 | 0,585366 |

14.
A = Carta con As | |
B= Carta con Figura | |
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P(A) = 4/52 | | |
| | |P(B) = 12/52 | | |
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P(AóB) = 4/52 + 12/52 = 16/52 |

15.
| | C
S

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