Estadistica

Páginas: 7 (1665 palabras) Publicado: 2 de agosto de 2011
INGENIERIA 0.4 MBA 0.3 ADMINISTRACION 0.45 MERCADOTECNIA 0.2
D A E B F C G (1) (2) (3) (4)

P (A) = P (1) n P (2)
P (B) = P (2) n P (3)
P (C) = P (3) n P(4)
P (D) = P (1) – P (A)
P (E) = P (2) – P (A) – P (B)
P (F) = P (3) – P (B) – P (C)
P (G) = P (4) – P (C)

P (A) = P (1) n P (2)
= 0.4 * 0.3
= 0.12

P (B) = P (2) n P (3)
= 0.3 * 0.45
= 0.135

P (C) = P (3) n P (4)
= 0.45 * 0.2
= 0.09

P (D) = P (1) – P (A)
= 0.4 – 0.12
= 0.28

P (E) = P (2) – P(A) – P (B)
= 0.3 – 0.12 – 0.135
= 0.045

P (F) = P (3) – P (B) – P (C)
= 0.45 – 0.135 – 0.09
= 0.225

P (G) = P (4) – P (C)
= 0.2 – 0.09
= 0.11

(1) (2) (3)
TACOS 0.25 PIZZA 0.5 HAMBURGUESA 0.35F B G C H
A
E D

IPOLLO 0.4

(4)
P (A) = P (2) n P (3) n P (4)
P (B) = P (1) n P (2)
P (C) = P (2) n P (3) – P (A)
P (D) = P (3) n P (4) – P (A)
P (E) = P (2) n P (4) – P (A)
P (F) = P (1) – P (B)
P (G) = P (2) – P (A) – P (B) – P (C) – P (E)
P (H) = P (3) – P(A) – P (C) – P (D)
P (I) = P (4) – P (A) – P (D) – P (E)

P (A) = P (2) n P (3) n P (4)
= 0.5 * 0.35 * 0.4
= 0.07

P (B) = P (1) n P (2)
= 0.25 * 0.5
= 0.125

P (C) = P (2) n P (3) – P (A)
= 0.5 * 0.35 – 0.07
= 0.105

P (D) = P (3) n P (4) – P (A)
= 0.35 * 0.4 – 0.07
= 0.015

P (E) = P (2) n P (4)– P (A)
= 0.5 * 0.4 – 0.07

P (F) = P (1) – P (B)
= 0.25 – 0.125
= 0.125

P (G) = P (2) – P (A) – P (B) – P (C) – P (E)
= 0.5 – 0.07 – 0.125 – 0.105 – 0.13
= 0.07

P (H) = P (3) – P (A) – P (C) – P (D)
= 0.35 – 0.07 – 0.105 – 0.015
= 0.16

P (I) = P (4) – P (A) – P (D) – P (E)
= 0.4 – 0.07 – 0.015 –0.13
= 0.185

= 0.13

JOAQUIN LOPEZ DORIGA 0.35 NOVELAS 0.25 JAVIER ALATORRE 0.3
(1) (2) (3)


D A EB F

C

G

(4)SERIES 0.4

P (A) = P (1) n P (2)
P (B) = P (2) n P (3)
P (C) = P (2) n P (4)
P (D) = P (1) – P (A)
P (E) = P (2) – P (A) – P (B) – P (C)
P (F) = P (3) – P (B)
P (G) = P (4) – P (C)

P (A) = P (1) n P (2)
= 0.35 * 0.25
= 0.087

P (B) = P (2) n P (3)
= 0.25 * 0.3
= 0.075

P (C) = P (2) n P (4)
=...
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