Estructuras

Páginas: 8 (1905 palabras) Publicado: 10 de diciembre de 2012
ANALISIS DE ESTRUCTURAS
Figura P6.1
3m

84 KN
1.25m
C
A
B
4m

Nodo B

∑Fy=84sen 67.39+ FBc sen75.74=0
FBC= -84sen67.39sen 75.742=80 KN
∑Fx = -84cos67.39-80cos75.74+FBA=0
FBA= 84cos67.39-80cos75.74
FBA= 52KN

Nodo C


∑Fy=-80sen 53.13+ FCA sen90=0
FCA= -80sen53.13sen 90=63.99 KN



A

80 kN
64 kN
52 kN
C
B
84 KN





945 Lbs
Figura P6.2A

C
B
3.75ft
12ft
9ft

Nodo A
∑Fy=945sen 53.14+ FBc sen75.76=0
FBC= 945sen53.14sen 75.76=780.06 Lb
∑Fx = 780.06cos75.76-945cos53.14+FAB=0
FAB= 780.06Cos75.76-45cos53.14
FAB= 374.98 Lb








Nodo B

∑Fy = -374cos36.86+FBc=0
FBc= 374Cos36.86
FBc= 300.02 Lb





945 Lbs


A

780 Lb
300 Lb
375 Lb
C
BA
Figura P6.3
B
C
4m
4.5m
3m
1.92 KN

Nodo A


∑Fy=-1.92Sen 98.78+ FAB Sen25.06=0
FAB= 1.92Sen 61.92Sen 25.06=3.99 KN
∑Fx = -1.92Cos61.92+3.99Cos25.06+FAc=0
FAB= 1.92Cos61.92-3.99cos25.06
FAc= 2.71KN


Nodo B

∑Fx = -3.99Cos53.13 +FBC=0
FBc= 3.99cos53.13
FBc= 2.39KN





A

3.99kN
2.71 kN
2.39 kN
C
B
1.92 KNFigura P6.4
4 Kips
1 Kip
1 Kip
B

2.4 Kips
F
E
D
C
A
6.4 ft
12 ft
12 ft

Y

Nodo A

X


∑Fy=-1Sen 90+ FAD Sen270=0
FAD= 1Sen 90Sen 270= 1 Kips
∑Fx = -1Cos90+1Cos270+FAB=0
FAB= 1Cos90-1cos270
FAB= 0Kips


Nodo B

Y

X
∑Fy=-4Sen 61.93+4Sen61.93+ FBD Sen270=0
FBD= 4Sen 61.93-45Sen61.93Sen 56.14= 0 Kips



Nodo D∑Fy=-4Sen 90-2.4Sen270=0
∑Fy=6.4Kips







1 Kip
4 Kips
1 Kip

A
B
C
0
0 Kip

6.4 Kip
6.4 Kips
1 kip
F
E
1 Kip
D

2.4 Kips



10.8Kips
10.8 Kips

35 ft
Figura p6.5
12 ft
22.5 ft

Nodo C



∑Fy= 10.8+ FFD Sen18.920=0
FAB= 10.8Sen 18.92= 33.3 Kips
∑Fx = -33.3Cos18.92+FCB=0
FAB= 33.3Cos18.92
FAB= 31.5Kips



∑Fy=-10.8Sen 90+ FBDSen270=0
FAB= 10.8Sen 90Sen 270= 10.8 Kips
∑Fx = -10.8Cos90+10.8Cos270+FBA=0
FBA= 1Cos90-10.8cos270
FBA= 0Kips

Nodo B

Nodo D



∑Fy=-33.3Sen18.92+ FAD Sen28.07=0
FAB= 33.3Sen 71.08Sen 61.93= 35.7 Kips

10.8Kips
10.8 Kips

31.5 Kips
31.5 kips
B

33.3 Kips
10.8 Kips
35.7 Kips
C
D
A




B
A
Figura P6.6
2.50m
900N
900N
F
C
E
D
2.50m

3m∑Fy= 900Sen 36.86+ FAC Sen53.13=0
FAB= -900Sen36.86Sen 53.13= 674.8N
∑Fx =-900Cos36.86-674.8Cos53.13+FAD=0
FAD = 900Cos36.86+674.8Cos53.13
FAB = 1124.9 N

Nodo A




Nodo B



∑Fy= 0

∑Fx= 0

Nodo C




∑Fy= -674.145Sen 53.14+900Sen36.80+ FCE Sen53.14+900Cos36.86=0
FAB= 674.145Sen53.14-900Sen36.80-900Cos36.86Sen53.14= 2024.31N
∑Fx =-900Cos36.86-900Cos36-674Cos53.8+2024.3Cos53.14+FCF=0
FAD = =-900Cos36.86-900Cos36-674Cos53.8+2024.3Cos53.14
FAB= 2250 N

















A
900N
0
B

675 N
2025 N
2250 N
900 N
1125 N
C
900N
2.50m
E
F
D
675N
0
C
E












8.4KN
AFigura P6.7
D
C
B
8.4KN
2.8m
4.5m
4.5m

Nodo A

∑Fy= -8.4Sen 58.1+ FAC Sen31.8=0
FAB= 8.4Sen58.1Sen 31.8= 13.53KN
∑Fx =-8.4Cos58.1-13.538Cos31.8-FAB=0
FAB = 8.4Cos58.1+13.53Cos31.8
FAB = 15.48KN






Nodo B

∑Fy= 15.4Sen 58.1+ FBD Sen270=0
FAB= 15.4Sen58.1Sen 270= 13.09KN
∑Fx =-15Cos58.1-13.09Cos270+FBC=0
FBC = 15Cos58.1-13.09Cos270
FAB = 8.13KN

Nodo C∑Fy= -13.5Sen 90+ FCD Sen58.1=0
FAB= 13.5Sen90Sen 581= 15.90 KN
∑Fx =-13.5Cos90-15.90Cos58.1-FCB=0
FAB = 13.5Cos90+15.90Cos58.1
FAB = 8.4KN+8.13KN =16.53






15.90 kN
13.50 kN
16.80 kN
13.50 kN
15.90 kN
D
8.4KN
8.4KN
B
C
A


Figura P6.8
693 Lbs
E
D
C
B
A
12 ft
11 ft
5ft
5ft

Nodo B


∑Fy= -693Sen 53.14+ FBE Sen75.6=0...
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