Fisica Ondas

Encontrar las expresiones matemáticas de la velocidad y la aceleración, evaluar para t=2,5[s] y gráficar .
x1t=0.025cos20t-0.93cm
x2t=0.025sin5πt-1.67cm
a. La posición, velocidad yaceleración de la particula a t=5[s]
b. La ecuación de onda superpuesta con x2t=0.010sin5πt-1.67cm, gráfiquela
c. La energía cinética y potencial de la onda superpuesta
V1(t)=x1(t)=-0.5sin⁡(20t-0.93)[cms]

a1(t)= x1(t)=-10cos⁡(20t-0.93)[cms2]

V2t= x2t=0.125πcos5πt-1.67[cms]

a2(t)= x2(t)=-0.625π2sin5πt-1.67[cms2]

Evaluación
t=2.5[s]x1t=0.025cos20t-0.93cm
x1t=0.009[cm]
x2t=0.025sin5πt-1.67cm
x2t=0.002[cm]
V1(t)= x1(t)=-0.5sin⁡(20t-0.93)[cms]
V1(t)=0.465[cms]
a1(t)= x1(t)=-10cos⁡(20t-0.93)[cms2]a1t=-3.665[cms2]
V2t= x2t=0.125πcos5πt-1.67[cms]
V2t=0.390[cms]
a2(t)= x2(t)=-0.625π2sin5πt-1.67[cms2]
a2(t)=0.610[cms2]
t=5[s]
x1t=0.025cos20t-0.93cm
x1t=0.002[cm]x2t=0.025sin5πt-1.67cm
x2t=0.025[cm]
V1(t)= x1(t)=-0.5sin⁡(20t-0.93)[cms]
V1(t)=0.496[cms]
a1(t)= x1(t)=-10cos⁡(20t-0.93)[cms2]
a1t=-1.096[cms2]
V2t= x2t=0.125πcos5πt-1.67[cms]V2t=0.038[cms]
a2(t)= x2(t)=-0.625π2sin5πt-1.67[cms2]
a2t=-6.138[cms2]

Puntos Corte:
Eje x:
V1t= x1t=-0.5sin20t-0.93cms
0=-0.5sin⁡(20t-0.93)[cms]
t=(kπ+0.93)/20[s]
a1(t)=x1(t)=-10cos⁡(20t-0.93)[cms2]
0=-10cos⁡(20t-0.93)[cms2]
t=2k+12π+0.9320[s]
V2t= x2t=0.125πcos5πt-1.67[cms]
0=0.125πcos5πt-1.67[cms]
t=2k+12π+1.675π[s]
a2(t)=x2(t)=-0.625π2sin5πt-1.67[cms2]
0=-0.625π2sin5πt-1.67[cms2]
t=kπ+1.675π[s]
Eje y.
t=0[s]
V1t=0.4[cms]
a1t=-5.978[cms2]
V2t=-0.038[cms]
a2t=6.138[cms2]

Onda Superpuesta.x1t+x2t=(0.025cos20t-0.93+0.010sin5πt-1.67)cm

Energía Cinética Y Potencial
VT=XT=0.125πcos5πt-1.67-0.625π2sin5πt-1.67[cms]
Ec=12mv2
Ec=12m0.125πcos5πt-1.67-0.625π2sin5πt-1.672[J]
Ep=mgh
Ep=0.05m[J]