fisica

*Cálculo del área de la base:
A_b=a_b±∆a_b donde:
a_b=(πd^2)/4 a_b=(3.14〖x(38.4)〗^2)/4 a_b=4630.1184/4 a_b=1157.5296〖mm〗^2
〖∆a〗_b=2(∆d/d)×a_b 〖∆a〗_b=2(0.025/38.4)×1157.5296〖∆a〗_b=57.8764/38.4 〖∆a〗_b=1.5072〖mm〗^2
A_b=a_b±∆a_b A_b=1157.5296〖mm〗^2±1.5072〖mm〗^2
*Cálculo del volumen del cilindro:
V=v±∆v donde:
v=a_b×h v=1157.5296×72.2v=83573.6371〖mm〗^3
∆v=v√(((∆a_b)/a_b )^2+(∆h/h)^2 ) ∆v=v√((1.5072/1157.5296)^2+(0.025/72.2)^2 )
∆v=v√0.000001815 ∆v=v0.0013473
∆v=83573.6371x0.0013473∆v=112.5987〖mm〗^3
V=v±∆v V=83573.6371〖mm〗^3±112.5987〖mm〗^3

*cálculo de la densidad del cilindro:
ρ=ϱ±∆ϱ ϱ=m/v ϱ=227.4g/(83.5736〖cm〗^3 ) ϱ=2.72095∆ϱ=ϱ√((∆m/m)^2+(∆v/v)^2 ) ∆ϱ=ϱ√((0.05/227.4)^2+(112.5987/83573.6371)^2 )
∆ϱ=2.72095√0.000001863561 ∆ϱ=2.72095x0.00136512
∆ϱ=0.00371443g/〖cm〗^3 ρ=ϱ±∆ϱ
ρ=2.72095 g/〖cm〗^3 ±0.00371443 g/〖cm〗^3Paralelepípedo Masa(g) A(mm) B(mm) C(mm)
x_1 379.1±0.5g 51.7 52.1 51.7
x_2 379.2±0.5g 51.4 52.2 52.0
x_3 379.1±0.5g 51.9 52.0 50.8
x_4 379.3±0.5g 50.9 50.8 50.6
x_5 379.2±0.5g 51.6 52.3 51.8
Promedio m̅=379.18 a ̅=51.5 b ̅=51.88 c ̅=51.38

*Cálculo del volumen del Paralelepípedo:
V=v±∆v donde:
v=abc v=51.5×51.88×51.38 v=137278.1116mm^3
∆v=v√((∆a/a ̅ )^2+(∆b/b ̅ )^2+(∆c/c ̅ )^2 )∆v=v√((0.025/51.5)^2+(0.025/51.88)^2+(0.025/51.38)^2 )
∆v=v√(7.1403456×〖10〗^(-7) ) ∆v=(137278.1116)×(8.4500565×〖10〗^(-4))
∆v=116.0007811〖mm〗^3
V=v±∆vV=137278.1116〖mm〗^3±116.0007811〖mm〗^3


*Cálculo de la densidad del paralelepípedo:
ρ=ϱ±∆ϱ donde:
ϱ=m/v ϱ=379.18g/(137.2781116cm^3 ) ϱ=2.76213g/cm^3
∆ϱ=ϱ√((∆m/m)^2+(∆v/v)^2 )∆ϱ=ϱ√((0.5/379.18)^2+(116.00078/137278.1116)^2 )
∆ϱ=2.76213√0.000002452832 ∆ϱ=2.76213×0.001566152
∆ϱ=0.0043259g/〖cm〗^3 ρ=ϱ±∆ϱ
ρ=2.76213 g/〖cm〗^3 ±0.0043259 g/〖cm〗^3...