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Páginas: 3 (643 palabras)
Publicado: 10 de febrero de 2013
MATEMÁTICAS 2º DE ESO ACTIVIDADES SM CON SOLUCIONES. TEMA - 1
Calcula: a) b) c) d) –10 – 2 · (7 – 5) = –(–6 – 1) · (–1 – 1) = (–9 + 3) : (–2) – 1 = –3 · (8 – 6 : 2) + 2 =
Solución: a) b) c) d)–10 – 2 · (7 – 5) = –10 – 2 · 2 = –10 – 4 = –14 –(–6 – 1) · (–1 – 1) = –(–7) · (–2) = –14 (–9 + 3) : (–2) – 1 = (–6) : (–2) – 1 = 3 – 1 = 2 –3 · (8 – 6 : 2) + 2 = –3 · (8 – 3) + 2 = –3 · 5 + 2 = –15 + 2 =–13
Realiza: a) –20 : [–3 · (6 – 8) + 4 · (–2) ] + (15 – 10 : 5 + 1) · (–1) = b) [(–4) · (–5 + 4 · 2 – 1) – 12 : (–3) + 5] · (–3 + 1) = Solución: a) –20 : [–3 · (6 – 8) + 4 · (–2)] + (15 – 10 : 5+ 1) · (–1) = –20 : [6 – 8] + (13 + 1) · (–1) = –20 : (–2) – 14 = –4 b) [(–4) · (–5 + 4 · 2 – 1) – 12 : (–3) + 5] · (–3 + 1) = [(–4) · 2 + 4 + 5] · (–2) = 1 · (–2) = –2 Calcula: a) 2 – [–(7 – 2) · 3 +1] – 4 : 2 = b) 3 – 3 · [–5 – (6 – 3) – 2] + 6 = c) (10 – 2) : (–4) – [–4 – (9 + 5 – 3) + 2] – 8 : (–2) = Solución: a) 2 – [–5 · 3 + 1] – 2 = 2 – [–15 + 1] – 2 = 2 – (–14) – 2 = 2 + 14 – 2 = 14 b) 3– 3 · [–5 – 3 – 2] + 6 = 3 – 3 · (–10) + 6 = 3 + 30 + 6 = 39 c) 8 : (–4) – [–4 – 11 + 2] + 4 = –2 – (–13) + 4 = –2 + 13 + 4 = 15
El triple de la suma de dos enteros es –36. Uno de ellos es el dobledel otro. ¿Cuáles son los enteros? Solución: La suma será –36 : 3 = –12. Como uno es el doble del otro, ? + 2 · ? = –12 ; 3 · ? = –12 Uno es –4 y el otro es –8. Calcula: 3 – [(–3) + 3 · (–2 + 6) – 10 ]· [–9 : (–4 – 2 · 3 + 7) + 1] = Solución: 3 – [(–3) + 3 · (–2 + 6) – 10] · [–9 : (–4 – 2 · 3 + 7) + 1] = 3 – (–3 + 3 · 4 – 10) · [–9 : (–4 – 6 + 7) + 1] = 3 – (–3 + 12 – 10) · [–9 : (–3) + 1] = 3 –(–1) · 4 = 3 + 4 = 7
Resuelve las siguientes operaciones: a) –6 + (–5 – 1 + 3) · (–2) + [–9 : (–3) ] = b) –30 : (10 – 6 : 2 – 1) – [–4 – 2 · (–5) ] = Solución: a) –6 + (–5 – 1 + 3) · (–2) + [–9 :(–3) ] = –6 + (–3) · (–2) + 3 = –6 + 6 + 3 = 3 b) –30 : (10 – 6 : 2 – 1) – [–4 – 2 · (–5) ] = –30 : (10 – 3 – 1) – (–4 + 10) = –30 : 6 – 6 = –5 – 6 = –11 El cociente de dos números es –3 y su...
Calcula: a) b) c) d) –10 – 2 · (7 – 5) = –(–6 – 1) · (–1 – 1) = (–9 + 3) : (–2) – 1 = –3 · (8 – 6 : 2) + 2 =
Solución: a) b) c) d)–10 – 2 · (7 – 5) = –10 – 2 · 2 = –10 – 4 = –14 –(–6 – 1) · (–1 – 1) = –(–7) · (–2) = –14 (–9 + 3) : (–2) – 1 = (–6) : (–2) – 1 = 3 – 1 = 2 –3 · (8 – 6 : 2) + 2 = –3 · (8 – 3) + 2 = –3 · 5 + 2 = –15 + 2 =–13
Realiza: a) –20 : [–3 · (6 – 8) + 4 · (–2) ] + (15 – 10 : 5 + 1) · (–1) = b) [(–4) · (–5 + 4 · 2 – 1) – 12 : (–3) + 5] · (–3 + 1) = Solución: a) –20 : [–3 · (6 – 8) + 4 · (–2)] + (15 – 10 : 5+ 1) · (–1) = –20 : [6 – 8] + (13 + 1) · (–1) = –20 : (–2) – 14 = –4 b) [(–4) · (–5 + 4 · 2 – 1) – 12 : (–3) + 5] · (–3 + 1) = [(–4) · 2 + 4 + 5] · (–2) = 1 · (–2) = –2 Calcula: a) 2 – [–(7 – 2) · 3 +1] – 4 : 2 = b) 3 – 3 · [–5 – (6 – 3) – 2] + 6 = c) (10 – 2) : (–4) – [–4 – (9 + 5 – 3) + 2] – 8 : (–2) = Solución: a) 2 – [–5 · 3 + 1] – 2 = 2 – [–15 + 1] – 2 = 2 – (–14) – 2 = 2 + 14 – 2 = 14 b) 3– 3 · [–5 – 3 – 2] + 6 = 3 – 3 · (–10) + 6 = 3 + 30 + 6 = 39 c) 8 : (–4) – [–4 – 11 + 2] + 4 = –2 – (–13) + 4 = –2 + 13 + 4 = 15
El triple de la suma de dos enteros es –36. Uno de ellos es el dobledel otro. ¿Cuáles son los enteros? Solución: La suma será –36 : 3 = –12. Como uno es el doble del otro, ? + 2 · ? = –12 ; 3 · ? = –12 Uno es –4 y el otro es –8. Calcula: 3 – [(–3) + 3 · (–2 + 6) – 10 ]· [–9 : (–4 – 2 · 3 + 7) + 1] = Solución: 3 – [(–3) + 3 · (–2 + 6) – 10] · [–9 : (–4 – 2 · 3 + 7) + 1] = 3 – (–3 + 3 · 4 – 10) · [–9 : (–4 – 6 + 7) + 1] = 3 – (–3 + 12 – 10) · [–9 : (–3) + 1] = 3 –(–1) · 4 = 3 + 4 = 7
Resuelve las siguientes operaciones: a) –6 + (–5 – 1 + 3) · (–2) + [–9 : (–3) ] = b) –30 : (10 – 6 : 2 – 1) – [–4 – 2 · (–5) ] = Solución: a) –6 + (–5 – 1 + 3) · (–2) + [–9 :(–3) ] = –6 + (–3) · (–2) + 3 = –6 + 6 + 3 = 3 b) –30 : (10 – 6 : 2 – 1) – [–4 – 2 · (–5) ] = –30 : (10 – 3 – 1) – (–4 + 10) = –30 : 6 – 6 = –5 – 6 = –11 El cociente de dos números es –3 y su...
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