Ing. Civil

CALCULO DE CAMARA P7


PREDIMENSIONAMIENTO


h´ = 0.60



h2 = 6.00
ω
b c ћ =
t3ℓ2 = 4.00 t2 t4 р´


t1
a d

ℓ1 = 5.00



f´c = 210 kg/cm2 K6 = 72.55
fy = 1400 kg/cm2 γ = 2.00
K2 = 8.52 C = 1/3Dimensiones y Cargas Tentativas

Supuesto # 1
t1 = t2 = d + d´
ω1 = ω3 = ω0 = γ h = 12.00 Ton/m2
h = h´+h2+ℓ2/2 рh = 8.60 m
р´ = C γ ћ = 5.73 Ton/m2
MFa d = 1/12 ωo ℓ21 = 25.00 Ton m
MFa b = 1/12 р´ ℓ22 = 7.64Ton m
Inercia i =bh3/ 12= 0.08 8
kab = i / ℓ2 2.08
kad = i / ℓ1 1.67 ∑ k = 3.75
δab = kab/∑ k = 0.56
δad = kad/∑ k = 0.44

Ъ Ъ
0.56 0.44 0.56 0.44
25.00 7.64
-13.89 -11.11 -4.25 -3.40M1 = ω0 ℓ2 / 8 - Mb =
M1 = M℄ bc = M℄ bc = 21.91 Ton m/m
Mωb = 13.89 , Ma , Mр´b = 3.40 (del cual se toma la mitad)
(Mb = δba MFbc), ( Mb = δbc MFba)
Ma = Mωa + Mр´a = 17.29 Ton m/m



17.2921.91
MLUZ


Mr = b d2/ K6 =
Luz: dREQ = 39.87 ≈ 40.00 cm
Pared: dREQ = 35.41 ≈ 35.00 cm
Con d´= 7.00 t1 = 47.00 t2 = 42.00 cm

Supuesto # 2

t1 = 50 cm k1= t31 /ℓ1 = 0.025
t2 = 40 cm k2= t32 / ℓ2 = 0.016
ℓ1 = 5.00 m δ1 = k1 / ∑ k = 0.61
ℓ2 = 4.00 m δ2 = k2 / ∑ k = 0.39

MFLUZ = 25.00 MFPARED = 7.64
Mωb = δba MFbc = 9.76 Mрb = δbc MFba = 4.66

MLUZ = ωoℓ2 / 8 - Mωb - Mрb/2= 25.41 d REQ = 42.94 cmMAP = Mωb + Mрb = 14.42 d REQ = 32.34 cm

Se adapta
como espesores: paredes: t2= 40.00 cm
placas: t1= 50.00 cm
como luces de cálculo: ℓ2 = 4.00 m
ℓ1 = 5.00 m

t2 = 0.40 0.40 = t2
ℓL = 4.600.50 = t1

b c

ℓ2 = 4.00 3.50
= hL


a d
0.50 = t1


ℓ1 = 5.00

Árealibre: ℓL*hL = 16.1 m2

Cargas, Superposición de Efectos












b c...