integrales

INTEGRALES DE MONOMIOS ALGEBRAICOS
2-. = =
4-. = = =
6-. = = =
8-. = = ==
10-. = = = =
12-. = = =
14-. = = = =
16-. = = = =
18-. = = = = =
20-. = == = =
22-. = = = = =
24-. = = = = =
26-. = = = = =
30-. = = = = =
32-. = =
34-. = = = = =
36-. = =
40-. = = dy= = =INTEGRALES QUE CONDUCEN A LA FUNCION LOGARITMO NATURAL
1-. = =

2-. = =

3-. = = = =
es unaconstante
4-. = =

5-. = =

6-. = 6 =

7-. = =

8-. = =


CASO GENERAL
1-. = =

2-. = =3-. = =

4-. = =

5-. = =

6-. = =

7-. = = factorizar

8-. = =



NOMBRE: JUAN MANUEL GAMEZ ROMO


MATRICULA: 131547MATERIA: CALCULO II


PROFESOR: CARLOS LOPEZ RUVALCABA







Página 7

Determinar la ecuación de la recta tangente a la gráfica de f en un punto dado. Utilizar aproximación lineal paracompletar la gráfica.
1)
F(x) =, (2,4)
F’(x) = 2x
Mtg= f’ (2) = 2(2) = 4

Y – 4 = 4 (x-2)
Y= 4x – 8+4
Y= 4x - 4

f(1.9)=4(1.9) – 4 = 3.6
f(1.99)= 4(1.99) - 4 = 3.96
f(2)=4(2) – 4 = 4f(2.01) = 4(2.01) – 4 = 4.04
f(2.1) = 4(2.1) – 4 = 4.4



1.9
1.99
2
2.01
2.1

3.61
3.9601
4
4.0401
4.41

3.6
3.96
4
4.04
4.40



3)
F(x) =, (2,32)
F’(x) = 5
Mtg = f’ (2) = 5= 80

Y - 32 = 80(x – 2)
Y = 80x – 160 + 32
Y = 80x – 128

f(1.9) = 80(1.9) – 128 = 24
f(1.99) = 80(1.99) – 128 = 31.2
f(2) = 80(2) -128 = 32
f(2.01) = 80(2.01) – 128 = 32.8
f(2.1) =80(2.1) – 128 = 40




1.9
1.99
2
2.01
2.1

24.79099
31.2079
32
32.8080
40.8410

24
31.2
32
32.8
40.0



5)

T(x) = cos2(x-2)+sen2


1.9
1.99
2
2.01
2.1

0.94...