Karnauth

SIMPLIFICACION POR EL METODO DE KARNOUTH:
| A | B | C | D | Y1 | Y2 | Y3 |
0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 |
1 | 0| 0 | 0 | 1 | 0 | 0 | 1 |
2 | 0 | 0 | 1 | 0 | 0 | 0 | 0 |
3 | 0 | 0 | 1 | 1 | 0 | 1 | 0 |
4 | 0 | 1 | 0 | 0 | 0 | 1| 0 |
5 | 0 | 1 | 0 | 1 | 1 | 0 | 0 |
6 | 0 | 1 | 1 | 0 | 1 | 0 | 0 |
7 | 0 | 1 | 1 | 1 | 1 | 1 | 0 |
8 | 1 | 0| 0 | 0 | 0 | 1 | 0 |
9 | 1 | 0 | 0 | 1 | 0 | 0 | 0 |
10 | 1 | 0 | 1 | 0 | 0 | 0 | 1 |
11 | 1 | 0 | 1 | 1 | 1 | 0 |0 |
12 | 1 | 1 | 0 | 0 | 1 | 0 | 0 |
13 | 1 | 1 | 0 | 1 | 1 | 0 | 0 |
14 | 1 | 1 | 1 | 0 | 0 | 1 | 0 |
15 | 1 |1 | 1 | 1 | 0 | 0 | 1 |
Y1= (5, 6, 7, 11, 12, 13)
Y2= (3, 4, 7, 8, 14)
Y3= (0, 1, 10, 15)

Y1= (5, 6, 7, 11, 12, 13)Y1= ABC’+ AB’CD+ A’BD+A’BC
| 00 | 01 | 11 | 10 |
00 | 0 | 0 | 0 | 0 |
01 | 0 | 1 | 1 | 1 |
11 | 1 | 1 | 0 | 0|
10 | 0 | 0 | 1 | 0 |

Y2= (3, 4, 7, 8, 14)
Y2= ABCD’+ A’CD+ A’BC’D+ AB’C’D’
| 00 | 01 | 11 | 10 |
00 | 0 | 0| 1 | 0 |
01 | 1 | 0 | 1 | 0 |
11 | 0 | 0 | 0 | 1 |
10 | 1 | 0 | 0 | 0 |

Y3= (0, 1, 10, 15)
Y3= A’ C’+ABCD+AB’CD’
| 00 | 01 | 11 | 10 |
00 | 1 | 1 | 0 | 0 |
01 | 0 | 0 | 0 | 0 |
11 | 0 | 0 | 1 | 0 |
10 | 0 | 0 | 0 | 1 |