los mejores cod c


Ejercicio 1.2.1 Usar el metodo de falsa posicion para encontrar una aproximacion de la raiz positiva de la siguiente ecuacion; en [0,1.5], con una tolerancia de 10⁻⁵, utilizar 7 decimales.f(x)=x¹⁰-1









n
a
b
f(a)
f(b)
Xn
f(Xn)
f(a)*f(Xn)
 
Er
1
0
1.5
-1
56.6650391
0.0260123
-1
1
>0
 
2
0.0260123
1.5
-1
56.6650391
0.0515735
-1
1
>00.4956266
3
0.0515735
1.5
-1
56.6650391
0.0766914
-1
1
>0
0.3275191
4
0.0766914
1.5
-1
56.6650391
0.1013737
-1
1
>0
0.2434783
5
0.1013737
1.5
-1
56.6650391
0.125628-1
1
>0
0.1930644
6
0.125628
1.5
-1
56.6650391
0.1494617
-1
1
>0
0.1594636
7
0.1494617
1.5
-1
56.6650391
0.1728821
-1
1
>0
0.1354704
8
0.1728821
1.5
-156.6650391
0.1958964
-0.9999999
0.9999999
>0
0.117482
9
0.1958964
1.5
-0.9999999
56.6650391
0.2185115
-0.9999998
0.9999997
>0
0.1034962
10
0.2185115
1.5
-0.999999856.6650391
0.2407345
-0.9999993
0.9999991
>0
0.0923133
11
0.2407345
1.5
-0.9999993
56.6650391
0.2625721
-0.9999984
0.9999977
>0
0.083168
12
0.2625721
1.5
-0.999998456.6650391
0.284031
-0.9999966
0.999995
>0
0.0755513
13
0.284031
1.5
-0.9999966
56.6650391
0.3051177
-0.999993
0.9999896
>0
0.0691101
14
0.3051177
1.5
-0.999993
56.66503910.3258386
-0.9999865
0.9999795
>0
0.0635925
15
0.3258386
1.5
-0.9999865
56.6650391
0.3462001
-0.9999753
0.9999618
>0
0.0588143
16
0.3462001
1.5
-0.9999753
56.66503910.3662083
-0.9999566
0.9999319
>0
0.0546361
17
0.3662083
1.5
-0.9999566
56.6650391
0.3858691
-0.9999268
0.9998834
>0
0.050952
18
0.3858691
1.5
-0.9999268
56.66503910.4051884
-0.9998807
0.99980751
>0
0.0476798
19
0.4051884
1.5
-0.9998807
56.6650391
0.4241719
-0.9998115
0.99969222
>0
0.0447543
20
0.4241719
1.5
-0.9998115
56.6650391...