Malacate Ab
a) punto C
b) punto E
C
35 in
b
E Dd a
76 in 8 in
[pic]= tan^-1 (35/84)
[pic]= tan^-1 (0.416666666)
[pic]= 22.61
Fy = sen 22.61°(260 lb) = 100 lb
Fx = cos 22.61° (260lb) = 240.01 lb
M C/D = (240 lb) (35 in) + (100 lb) (-8 in)
M C/D = 840 lb.in - 800 lb.in
MC/D = 7600 lb.in
M E/D = (240 lb) (0 in) + (100 lb) (76 in)
M E/D = 7600 lb.in
Una fuerza P de 3 lb se aplica a una palanca quecontrola la barrena de una barredora de nieve. Determine el momento de p respecto de a cuando [pic] = 30°
P= 3 lb 3.5 in
[pic]P
4.8 in
A
Fyp c.o
Fxp c.a
Fx
4.8 Fxp=c.a = (cos 60°) (3lb) = 1.5 lb
Fx
3.4 Fxp= c.o = (sen 60°) (3lb) = 2.59 lb
M A/B =(1.5 lb) (4.8 in) + (2.59 lb) (3.4 in)
M A/B = 16.006 in
-----------------------
[pic]
60°
Regístrate para leer el documento completo.