MATE-FINANCIERA-RESOL-PROBLEMAS

Tarea Académica :
C1= 20000
TNA= 18% c.m t1= 6 meses + 12 meses= 18 meses
m= 12 n= 18

S=C*(1+ TNA/m)^n
S=20000*(1+ (18%)/12)^18S=26146.81272

C2= 15000
TNM= 2% c.q t2= 3 meses + 12 meses= 15 meses
m= 2 n= 30

S=C*(1+ TNM/m)^n
S=20000*(1+ (2%)/2)^30S=20217.73373

Si realizara la compra de deuda:
C1= 20000+15000=35000
TNA= 1% c.d t= 12 meses
m= 30 n= 360S=C*(1+ TNA/m)^n
S=35000*(1+ (1%)/30)^360
S=39461.60069
Rpta:
Micaela ahorraría: $.46364.54645 – $39461.60069 =S/.6902.94576
Datos:
I= 2850

C=?
TNA = 8% c.d t=1 año y medio
m= 360 n= 540

C=I/((1+TNA/m)^n- 1)C=2850/((1+(8%)/360)^540- 1)
Rpta: C=22356.12903
C= 22356.12903
S=C + 20%*C = 120%*C = 120%* 22356.12903 =26827.35484
TNA = 8% c.d t=?
m= 360 n=?n=(Ln (S/C))/Ln(1+TNA/m)

n=(Ln (26827.35484/22356.12903))/Ln(1+(8%)/360)
n = 820.53654405 ≈ 821Rpta:
Tendrian que haber pasado: 821 – 540 = 281 días más.
C=? $49857.69 $50985.34
0 3er8avo 12avo
mes mes mes

C= $49857.69
S= $50985.34
TNA = c.d t=mes 4 + mes 5+ mes 6+ mes 7 + mes 8= 5 meses
m= 360 n= 150
TN=m*(√(n&S/C)-1)
TNA=360*(√(150&50985.34/49857.69)-1)...