Matematica Matricez

REPUBLICA BOLIVARIANA DE VENEZUELA
MINISTERIO DEL PODER POPULAR PARA LA DEFENSA
UNIVERSIDAD NACIONAL EXPERIMENTAL POLITÉCNICA
DE LA FUERZA ARMADA
UNEFA NUCLEO CORO

IS2D-A

AlgebraAutor:Cristhian Flores
Armindo Quero

Falcon-coro octubre 2012
1. Dadas las matrices:
A = 425318967 y B = 21-13-4-11-3-2

Y el escalar α= - 3/5.Calcular:
a) A+B b) A-B c) α.A d) α.B e) α.A+ α.B f) α.A- α.B

a) A+B= 425318967 + 21-13-4-11-3-2 = 6346-371035

b) A-B= 425318967 -21-13-4-11-3-2 = 216059899

c)-3/5.A= 425318967 = -2.4-1.2-3-1.8—0.6-4.8-5.4-3.6-4.2

d) -3/5.B=21-13-4-11-3-2 = -1.2-0.60.6-1.82.40.6-0.61.81.2

e) -3/5.A= -2.4-1.2-3-1.8—0.6-4.8-5.4-3.6-4.2 + -3/5.B=-1.2-0.60.6-1.82.40.6-0.61.81.2 =

-3/5.A+3/5.B= -3.6-1.8-2.4-3.61.8—4.2-6-1.8-3

f) -3/5.A= -2.4-1.2-3-1.8—0.6-4.8-5.4-3.6-4.2 - -3/5.B= -1.2-0.60.6-1.82.40.6-0.61.81.2

-3/5.A-3/5.B=-1.2-0.6-3.60-3-5.4-4.8-5.4-5.4
2. Dadas las matrices:

A = 2-12-102 B= 10-1-221
Calcular A.B

A.B= 2.1+-1.-1+2.-2 2.0+-1.2+2.1-1.1+0.-1+2(-2) -1.0+0.2+2.1

A.B= 2+1-40-2+2-1+0-40+0+2

A.B= -10-52

3.Hallar la matriz inversa de:

A= 210121012

210| 100121 | 010 012| 001 F1→ (-1).F2+F1

1-1-1 |1-10121 |010012 |001 F2→ (-1).F1+F2

1-1-1| 1-10032 | -120012| 001F2→ (-2).F3+F21-1-1| 1-1001-2|-12-2012| 001 F3→ (-1).F2+F3

1-1-1| 1-1001-2|-12-200 4| 1-23F1→ (1).F2+F1

10-3 |01-201-2 |-12-200 4 |1-23¼.F3

10-3| 01-201-2 |-12-200 1|1/4-1/23/4F2→2.F3+F2

10-3|01-2010 |-1/21-1/2001 |1/4-1/23/4F1→ (3).F3+F1

100|3/4-1/21/4010|-1/41-1/2001|1/4-1/23/4

A-1= 3/4-1/21/4-1/21-1/21/4-1/23/4

4. Dadas las matrices:
A = 412231302...