Matematicas

TALLER. ECUACIONES LINEALES CLAUDIA P BUITRAGO NCR 1472 1. Resolver las siguientes ecuaciones de primer grado. 1 -3(2x + 7) + (-5x + 6) -8 (1 – 2x) – (x- 3)=0 -6x – 21 -5x +6 – 8 + 16x – x + 3=0 4x-20 = 0 4x = 20 X = 20 4 X=5  2 ( x+21) – 1 (24x-20)=-21-2x 3 4 2x + 42 - 24x +20 = -21-2x 3 3 4 4 8x+168-72x+60 = -21-2x 12 -64x+108 = -21-2x 12 -64x+108 = 12(-21-2x) -64x+108 = -252-24x 108+252 =-24x+64x 360 = 40x 360 = x 40 9=x

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2. Resolver y graficar las siguientes inecuaciones de primer grado. 1 (6-x) (-3) +4 (-1x+7) >0 -18 + 3x – 4x + 28 >0 -x + 10 >0 -x>-10 X 6x – 3 4 3 6 -3x – 24 >24x – 6 mcm=12 12 12 12 -3x -24x > -6 + 24 -27x > 18

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-x > -18 = x < 18 = x < 2 27 27 3 (-∞ , 2/3] -3 -2 -1 5 + 3x < 4 –x 3 x + 3x < 4 –5 4x < -1 x <-1 4 (-∞ , -1/4] -4 -3 0 1 2 2/3 3

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3. Graficar las siguientes rectas. Ecuación general de la recta Ax + By +36=0 pendiente (m)=-A/B 1  5(-2)-3y-15=0 -10-3y-15=03y=15+10 3y=25 y=25/3  5(-1)-3y-15=0 -5-3y-15=0 3y=15+5 3y=20 y=20/3  5(0)-3y-15=0 5-3y-15=0 3y=15 y=15/3 y=5  5(1)-3y-15=0 5-3y-15=0 3y=15-5 3y=10 y=10/3  5(2)-3y-15=0 10-3y-15=0 3y=15-10 3y=5 y=5/3 4(-2)+6y+12=0 -8+6y+12=0 6y=-12+8

9 8 7 6 5 4 3 2 1 0 -3 -2 -1 0 1 2 3

x -2 -1 0 1 2 y 25/3 20/3 5 10/3 5/3

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6y=-4 y= -4/6  4(-1)+6y+12=0 -4+6y+12=0 6y=-12+4 6y=-8 y= -8/6 4(0)+6y+12=0 0+6y+12=0 6y=-12 6y=-12/6 y=-2  4(1)+6y+12=0 4+6y+12=0 6y=-12-4 6y=-16 y=-16/6  4(2)+6y+12=0 8+6y+12=0 6y=-12-8 6y=-20 y=-20/6 3  6(-2)-18y+36=0 -12-18y+36=0 -18y=12-36 -18y=-24 y= -24/18 6(-1)-18y+36=0 -6-18y+36=0 -18y=6-36 -18y=-30 y= -30/18  6(0)-18y+36=0 0-18y+36=0 -18y=12-36 -18y=-36 y= -36/18 y= -2  6(1)-18y+36=0 6-18y+36=0 -18y=-6-36 -18y=-42 y= -42/18

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0 -1 0 - 1/2-1 -1 1/2 -2 -2 1/2 -3 -3 1/2

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x -2 -1 0 y -2 4/6 8/6

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0 -1 0 - 1/2 -1 -1 1/2 -2 -2 1/2 -3

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x -2 -1 0 1 2 y - 24/18 30/18 2 42/18...