Matrices

CORRECCIÓN PARCIAL
1. Dada la matriz H halle el determinante
H=23-4130132184576-2
[H]= A12 (c12) +B 22 (c22) + D32 (c32) + + E42 (c42)
C12=-1 1+2313312842856-256=-13*8*-2+1*4*5+3*2*6-(3*8*5+3*4*6+(1*2*-2)
C12= -1-48+20+36-(120+72-4)
C12= -18-188
C12= -1-180
C12= 180
c22=-1 2+2 2-412-42842856-256=2*8*-2+-4*4*5+1*2*6-(1*8*5+2*4*6+(-4*2*-2))
C22=-32-80+12-(40+48+16)
C22= -100-104
C12= -204
c32=-1 3+2 2-412-43133156-256=-12*1*-2+-4*3*5+1*3*6-(1*1*5+2*3*6+-4*3*-2)
C32= -1-4-60+18-(5+36+24)
C32= -1-46-65
C32= -1-111
C32= 111
c42=-1 4+22-412-43133128428=2*1*4+-4*3*2+1*3*8-(1*1*2+2*3*8+-4*3*4)
C42= 8-24+24-(2+48-48)
C42= 8 – 2
C42=6
[H]= 3(180) + 0 (-204) + 1(111)+ 7(6)
[H]= 540+0+111+42
[H]= 693
2. El menor de la matrizH en la posición 3,2.
H =23-4130132184576-2
H32=2-4131356-2
3. Resuelva la matriz de la ecuación AX=B
A=111123-11-1 X=xyz B=614-2[A]=1111112312-11-1-11=1*2*-1+1*3*-1+1*1*1-(1*2*-1+1*3*1+1*1*-1)
[A]= -2-3+1-(-2+3-1)
[A]= -4
[AX]=611611423142-21-1-21=6*2*-1+1*3*-2+1*14*1-(1*2*-2+6*3*1+1*14*-1)
[AX]= 12-6+14-(-4+18-14)
[AX]= - 4[AY]=161161143114-1-2-1-1-2=1*14*-1+6*3*-1+1*1*-2-(1*14*-1+1*3*-2+6*1*-1)
[AY]= -14-18-2-(-14-6-6)
[AY]= -34 + 26
[AY]= -8
[AZ]=11611121412-11-2-11=1*2*-2+1*14*-1+6*1*1-(6*2*-1+1*14*1+1*1*-2)
[AZ]= -4-14+6-(-12∓14-2)
[AZ]= -12

X =-4-4= 1
Y=-8-4= 2
Z=-12-4= 3
X=123
4. Resuelva el sistema:
x+y+z=6 x-y+z=2 2x+y-z=1
A=1111-1121-1 X=xyz B=621
[A]=111111-111-121-1211*-1*-1+1*1*2+1*1*1-(1*-1*2+1*1*1+1*1*-1)[A]= 1+2+1-(-2+1-1)
[A]= 4+2
[A]= 6
[AX]=611612-112-111-1116*-1*-1+1*1*1+1*2*1-(1*-1*1+6*1*1+1*2*-1)
[AX]= 6+1+2-(-1+6-2)
[AX]= 9 – 3
[AX]= 6[AY]=161161211221-1211*2*-1+6*1*2+1*1*1-(1*2*2+1*1*1+6*1*-1)
[AY]= -2+12+1-(4+1-6)
[AY]= 11 + 1
[AY]= 12
[AZ]=116111-121-1211211*-1*1+1*2*2+6*1*1-(6*-1*2+1*2*1+1*1*1)

[AZ]= -1+4+6-(-12+2+1)
[AZ]= 9 +9
[AZ]= 18
X =66= 1
Y =126= 2...