Maximos Y Minimos
1. f(x) = x3 − 3x + 2
f'(x) = 3x2 − 3 = 0
f''(x) = 6x
f''(−1) = −6 Máximo
f''(1) = 6 Mínimof(−1) = (−1)3 − 3(−1) + 2 = 4
f(1) = (1)3 − 3(1) + 2 = 0
Máximo(−1, 4) Mínimo(1, 0)
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