MEcanismos
A) σ x=-10 σy=18 τxy=9sr
Ilustración
C=-10+18/2=4 D-C=18-4=14 τmax=R= σ1=4+16.6=20.6
σ2=4-16.6=-12.6= 28.6 sr
(90+(90-32.7))=73.65
σ1=
σ2=
σm=
τmax=-
B) σ x=-12 σy=22 τxy=12 sr
C=-12+22/2=5 D-C=22-5=17 τmax=R= σ1=5+20.81=25.81σ2=5-20.81=-15.81
= 27.39 sr
(90+(90-35.22))=72.39 sr
σ1=
σ2=
σm=
τmax=-
C) σ x=-20 σy=-10 τxy=8 sr
C=20+(-10)/2=5 D-C=20-5=15 τmax=R= σ1=5+17=22σ2=5-17=-12 sr
= -30.96 scr
σ1=
σ2=
σm=
τmax=-
D) σ x=30 σy=-10 τxy=10 scr
C=30+ (-10)/2=10 D-C=30-10=20 τmax=R= σ1=10+22.4=32.4
σ2=10-22.4=-12.4scr
= 31.72 sr
σ1=
σ2=
σm=
τmax=-
E) σ x=10 σy=24 τxy=6 scr
C=10+24/2=17 D-C=24-17=7 τmax=R= σ1=17+9.22=26.22
σ2=17-9.22=7.78= -24.7 scr
(90+(90-40.6))=69.7
σ1=
σ2=
σm=17
F) σ x=9 σy=19 τxy=8 scr
C=9+19/2=14 D-C=19-14=5 τmax=R=σ1=14+9.4=23.4
σ2=14-9.4=4.6
= -16 (90+(90-(2*29)))=61 scr
σ1=
σ2=
σm=
τmax=-
A)
q = R1(X)−1 – 40(x – 4)−1 + 30(x – 8)−1 + R2(x – 14)−1 – 60(x – 18)−1
V =R1 – 40(x – 4)0 + 30(x – 8)0 + R2(x – 14)0 – 60(x – 18)0
M = R1x – 40(x – 4)1 + 30(x – 8)1 + R2(x – 14)1 – 60(x – 18)1
Para X=18 V=0 M=0
0=R1- 40+30+R2- 60 0=R1(8)- 40(14)+30(10)+4R2R1+R2=70 9R1+2R2=130 → R1=-1.43 R2=71.43
B)
q = R0(X)^−1 − M0(x)^−2 – 2000(x − 0.2)^−1 – 4000(x − 0.35)^0 + 4000(x − 0.5)^0
V = R0 − M0(X)^−1 – 2000(x − 0.2)^0 – 4000(x −...
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